錯誤：現有連接被FTP中的遠程主機強制關閉在C＃中？

Question

當我嘗試做多上傳我收到上述錯誤 在FTP我有兩個班一個是FTPdatatransfer等是FTPcommand 而在我的主法師我正在做這樣的事情

FTPCommand ftpcommand = new FTPCommand(ServerAddress, UserName, Password); 
ftpcommand.Login(); 
ftpcommand.sendCommand("CWD ", "/home/praveena/RMS"); 
ftpcommand.sendCommand("PASV");    

ftpcommand.sendCommand("STOR ","FTP.pdf");     
ftpcommand.sendCommand("STOR ","linux.pdf"); 
ftpcommand.sendCommand("QUIT"); 

一個上傳工作正常，而其他提供了上述錯誤

FTPCommand.cs

public void sendCommand(String command, params string[] strfilename) 
    { 


     string ServerAddress = "172.24.18.240"; 
     string UserName = "praveena"; 
     string Password = "praveena"; 


     if (command == "STOR ") //Uploading to Server 
     { 

      FTPDataTransfer ftpdatatransfer = new FTPDataTransfer(ServerAddress, UserName, Password, 10000, iport);    
      foreach (string dir in strfilename) 
      { 
       command = "STOR " + strfilename[0]; 
      } 

      Send(command);     
      ftpdatatransfer.Upload(strfilename[0]);     
      this.readResponse(); 

     } 
     else if (command == "MKD ") 
     { 
      command = "MKD " + strfilename[0]; 
      Send(command); 
      this.readResponse(); 
     } 

     else if (command == "CWD ") 
     { 
      command = "CWD " + strfilename[0]; 
      Send(command); 
      this.readResponse(); 
     } 

     else if (command == "NLST ") //Listing Files from Server. 
     { 
      FTPDataTransfer ftpdatatransfer = new FTPDataTransfer(ServerAddress, UserName, Password, 10000, iport); 
      foreach (string dir in strfilename) 
      { 
       command = "NLST " + "*"; 
      } 
      Send(command); 
      ftpdatatransfer.GetFilelist(); 
      this.readResponse(); 

     } 
     else 
     { 

      Send(command); 
      this.readResponse(); 
      if (command == "PASV") 
      { 
       iport = GetPort(); 
      } 


     } 


    } 



    public void Send(string command) 
    { 
     Byte[] cmdBytes = Encoding.ASCII.GetBytes((command + "\r\n").ToCharArray()); 
     clientSocket.Send(cmdBytes, cmdBytes.Length, 0); 
    } 


    public int GetPort() 
    { 
     int index1 = result.IndexOf('('); 
     int index2 = result.IndexOf(')'); 

     string ipData = this.result.Substring(index1 + 1, index2 - index1 - 1); 

     int[] parts = new int[6]; 

     int len = ipData.Length; 
     int partCount = 0; 
     string buf = ""; 

     for (int i = 0; i < len && partCount <= 6; i++) 
     { 
      char ch = char.Parse(ipData.Substring(i, 1)); 

      if (char.IsDigit(ch)) 
       buf += ch; 

      else if (ch != ',') 
       throw new WinFTPClient.FTPCommand.FtpException("Malformed PASV result: " + result); 

      if (ch == ',' || i + 1 == len) 
      { 
       try 
       { 
        parts[partCount++] = int.Parse(buf); 
        buf = ""; 
       } 
       catch (Exception ex) 
       { 
        throw new WinFTPClient.FTPCommand.FtpException("Malformed PASV result (not supported?): " + this.result, ex); 
       } 
      } 
     } 


     string ipAddress = parts[0] + "." + parts[1] + "." + parts[2] + "." + parts[3]; 

     int port = (parts[4] << 8) + parts[5];   

     return port; 
    } 

FTPdatatransfer.cs

public void Upload(string strfilename) 
    { 


     Thread thread = new Thread(new ThreadStart(() => UploadFile(strfilename))); 
     thread.Start(); 




    } 

    public void UploadFile(string strfilename) 
    { 


     Socket cSocket = createDataSocket(); 

     //open stream to read file 

     FileStream input = new FileStream(strfilename, FileMode.Open); 
     while ((bytes = input.Read(buffer, 0, buffer.Length)) > 0) 
     { 
      cSocket.Send(buffer, bytes, 0); 
     } 

     input.Close(); 
     if (cSocket.Connected) 
     { 
      cSocket.Close(); 
     } 

     // this.readResponse(); 

     MessageBox.Show("File Uploaded successfully"); 

    } 

public Socket createDataSocket() 
    { 


     IPAddress ipAddress = IPAddress.Parse("172.24.18.240"); 
     Socket socket = null; 
     IPEndPoint ep = null; 


     try 
     { 
      socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); 
      ep = new IPEndPoint(Dns.GetHostEntry(ipAddress).AddressList[0], port); 
      socket.Connect(ep); 
     } 
     catch (Exception ex) 
     { 
      // doubtfull.... 
      if (socket != null && socket.Connected) socket.Close(); 

      throw new WinFTPClient.FTPCommand.FtpException("Can't connect to remote server", ex); 
     } 

     return socket; 
    } 

Answer 1

最有可能的FTP服務器正在限制同時上傳的數量。沒有辦法從客戶端強制這一點。