錯誤如果超過2個輸入

Question

@echo off 
if not exist "c:\user_records" md c:\user_records 
if [%1]==[] goto ask 
set name=%~1 
set username=%~2 
if name==[] if username==[] (
@echo Error. I don't understand the perameters. Now switching to 
@echo Interactive mode 
goto int 
) 
goto save 
:ask 
@echo This program allows the user to create a username for them to use. 
@echo When asked, please enter your name and chosen username. The 
@echo program will create a .txt file with the chosen username as the title. 
:int 
set /p name="What is your name?" 
set /p username="What is your username?" 
:save 
if exist c:\user_records\%username%.txt (
@echo This username already exists! 
set /p username="Please enter another username:" 
) 
@echo %username%.txt was created 
@echo %name% >>c:\user_records\%username%.txt 
@echo %username% >>c:\user_records\%username%.txt 
@echo %date% %time% >>c:\user_records\%username%.txt 

如果用戶給出2個參數中的1個或多於2個，那麼它應該顯示一個錯誤消息，指出參數丟失並轉到int。但相反，它需要前兩個或只有一個。我該如何解決？

Answer 1

只是一個基本的解決方案

.... 
if not "%~2"=="" if "%~3"=="" goto :doSomething 
echo Error - Bad arguments 
goto :eof 
:doSomething 
.... 

如果您至少有兩個論點，但不是三個，然後開始工作，否則顯示錯誤和結束。

另外請注意，在你的代碼中，行

if name==[] if username==[] 

是錯誤的。 name只是一個字符串和一個變量的名字。您需要與環境變量關聯的值，即應使用%name%（調用set變量的批處理方式）。當批解析器到達該行時，它將看到%name%參考，並將其展開爲與name變量關聯的值。