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對於項目,我需要使用CoreLocation服務,但使用其他語言。但是,這個問題是一個無限的NSRunLoop。我試圖使用觀察員,但沒有任何成功。我沒有得到任何東西無法在控制檯應用程序中停止NSRunLoop
- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
所以我在運行循環中等待位置更新。我可以使用runUntilDate,但我需要確保用戶在接下來的3/5/10秒內點擊Ok。
所以,這裏是我的代碼:
#import <Foundation/Foundation.h>
#import <CoreLocation/CoreLocation.h>
@interface Location : NSObject <CLLocationManagerDelegate>
@property (nonatomic, retain)CLLocationManager *manager;
@property (nonatomic, retain)NSTimer *timer;
@end
@implementation Location
- (instancetype)init {
if (self = [super init]) {
_manager = [[CLLocationManager alloc] init];
_manager.delegate = self;
}
return self;
}
- (void)dealloc {
[_manager release];
[_timer release];
[super dealloc];
}
- (void)launch
{
[_manager startUpdatingLocation];
_timer = [NSTimer scheduledTimerWithTimeInterval:0.1
target:self
selector:@selector(checkIfUpdated:)
userInfo:nil
repeats:YES];
[_timer release];
[[NSRunLoop currentRunLoop] addTimer:_timer forMode:NSDefaultRunLoopMode];
[[NSRunLoop currentRunLoop] run];
}
- (void)checkIfUpdated:(NSTimer *)timer
{
if (_manager.location != nil) {
[timer invalidate];
[timer release];
NSLog(@"invalidate the timer %@", timer);
}
}
- (void)locationManager:(CLLocationManager *)manager didFailWithError:(NSError *)error
{
NSLog(@"Error %@", error.userInfo);
[_timer invalidate];
[_timer release];
}
@end
int main(int argc, const char * argv[]) {
Location *location = [[Location alloc] init];
[location launch];
NSString *str = [NSString stringWithFormat:@"%f, %f", location.manager.location.coordinate.latitude,
location.manager.location.coordinate.longitude];
[str release];
NSLog(@"%s", [str UTF8String]);
return 0;
}
預先感謝您。 乾杯
哦,謝謝,你真的救了屁股:) –