發送表單數據分開

Question

好吧，這是我正在嘗試acchomplish，（截至現在）我有用戶選擇圖像和圖像的大小，並上傳到服務器。我想要做的是在圖像被選擇並調整大小後停止腳本。然後，我想創建一個函數來上傳我選擇時調整大小的圖像。原因是我打算在我的表單中添加更多輸入文本，並且用戶已完成完成，然後我想要使用這些文件上傳圖像。注：我還沒有添加文字輸入會做後只是希望能夠sepearate上傳functions..I我不知道如何單獨的FORMDATA後部分

JAVASCRIPT

<script> 
function ResizeMe(){ 
var dataurl = null; 
var uniq = 'id' + (new Date()).getTime(); 
var filesToUpload = document.getElementById('input').files; 
var file = filesToUpload[0]; 

// Create an image 
var img = document.createElement("img"); 
// Create a file reader 
var reader = new FileReader(); 
// Set the image once loaded into file reader 
reader.onload = function(e) 
{ 
    img.src = e.target.result; 

    img.onload = function() { 
     var canvas = document.createElement("canvas"); 
     var ctx = canvas.getContext("2d"); 
     ctx.drawImage(img, 0, 0); 

     var MAX_WIDTH = 200; 
     var MAX_HEIGHT = 400; 
     var width = img.width; 
     var height = img.height; 

     if (width > height) { 
      if (width > MAX_WIDTH) { 
      height *= MAX_WIDTH/width; 
      width = MAX_WIDTH; 
      } 
     } else { 
      if (height > MAX_HEIGHT) { 
      width *= MAX_HEIGHT/height; 
      height = MAX_HEIGHT; 
      } 
     } 
     canvas.width = width; 
     canvas.height = height; 
     var ctx = canvas.getContext("2d"); 
     ctx.drawImage(img, 0, 0, width, height); 
     dataurl = canvas.toDataURL("image/jpeg",.2); 
     var blobBin = atob(dataurl.split(',')[1]); 
     var array = []; 
     for(var i = 0; i < blobBin.length; i++) { 
     array.push(blobBin.charCodeAt(i)); 
     } 
     var files = new Blob([new Uint8Array(array)], {type: 'image/jpg', name: "ddd"}); 
     // Post the data 
     var fd = new FormData(); 
     fd.append("image", files, uniq); 
     $.ajax({ 
      url: 'http:///www.***/upload.php', 
      data: fd, 
      cache: false, 
      contentType: false, 
      processData: false, 
      type: 'POST', 
      success: function(data){ 
       $('#form_input')[0].reset(); 
       location.reload(); 
      } 
     }); 
    } // img.onload 
} 
// Load files into file reader 
reader.readAsDataURL(file); 
} 
</script> 

Answer 1

代碼發送形式數據是

$.ajax({ 
    url: 'http:///www.***/upload.php', 
    data: fd, 
    cache: false, 
    contentType: false, 
    processData: false, 
    type: 'POST', 
    success: function(data){ 
     $('#form_input')[0].reset(); 
     location.reload(); 
    } 
}); 

該代碼是您將要放在一個單獨的函數中的代碼。要將它移動到其他地方，您必須確保它仍然可以訪問所有要發送的變量，即fd。 fd連接到幾個變量，全部返回到canvas。你說一次只能有一個畫布，所以我們可以使canvas成爲一個全局變量，然後從任何地方得到fd都很容易。

<script> 
    //Moved to global so that sendFormStuff will see it 
    var canvas = document.createElement("canvas"); 
    var ctx = canvas.getContext("2d"); 
    function ResizeMe(){ 
    var dataurl = null; 
    var uniq = 'id' + (new Date()).getTime(); 
    var filesToUpload = document.getElementById('input').files; 
    var file = filesToUpload[0]; 

    // Create an image 
    var img = document.createElement("img"); 
    // Create a file reader 
    var reader = new FileReader(); 
    // Set the image once loaded into file reader 
    reader.onload = function(e) 
    { 
     img.src = e.target.result; 

     img.onload = function() { 

     ctx.drawImage(img, 0, 0); 

     var MAX_WIDTH = 200; 
     var MAX_HEIGHT = 400; 
     var width = img.width; 
     var height = img.height; 

     if (width > height) { 
      if (width > MAX_WIDTH) { 
      height *= MAX_WIDTH/width; 
      width = MAX_WIDTH; 
      } 
     } else { 
      if (height > MAX_HEIGHT) { 
      width *= MAX_HEIGHT/height; 
      height = MAX_HEIGHT; 
      } 
     } 
     canvas.width = width; 
     canvas.height = height; 
     ctx.drawImage(img, 0, 0, width, height); 
     } // img.onload 
    } 
    function sendFormStuff() { 
     var dataurl = canvas.toDataURL("image/jpeg",.2); 
     var blobBin = atob(dataurl.split(',')[1]); 
     var array = []; 
     for(var i = 0; i < blobBin.length; i++) { 
     array.push(blobBin.charCodeAt(i)); 
     } 
     var files = new Blob([new Uint8Array(array)], {type: 'image/jpg', name: "ddd"}); 
     // Post the data 
     var fd = new FormData(); 
     fd.append("image", files, uniq); 
     $.ajax({ 
     url: 'http:///www.***/upload.php', 
     data: fd, 
     cache: false, 
     contentType: false, 
     processData: false, 
     type: 'POST', 
     success: function(data){ 
      $('#form_input')[0].reset(); 
      location.reload(); 
     } 
     }); 
    } 
    // Load files into file reader 
    reader.readAsDataURL(file); 
    } 
</script> 

所以真的所有我們在這裏所做的就是移動請求代碼到一個單獨的功能，使canvas和ctx（你被宣佈兩次，順便說一句），通過該功能進行訪問。