2016-08-02 80 views
1

爲什麼我不能執行這個簡單的更新查詢:MS Access 2007中使用逗號更新次數失敗

SQL = "UPDATE Table SET field=0,11 WHERE id=12456" 
db.Execute SQL, dbSeeChanges 

如果我的字段值設置爲0.11(帶小數點),更新查詢成功執行。

我的Access表字段數據類型是Number。

這裏是我的錯誤: 「3144 - 在UPDATE語句的語法錯誤」

+1

您可能希望看到這樣一個問題:http://stackoverflow.com/questions/11565335/ms -access-database-with-number-fields-in-a-language- – Bobort

回答

1

你需要寫一個不是逗號的,就像這樣:

SQL = "UPDATE Table SET field=0.11 WHERE id=12456" 
db.Execute SQL, dbSeeChanges 
+0

好的,但是如果我的值來自另一個源如表格。那麼值仍然是0,11。我應該用點逗號來點替換嗎? – wiz6

+0

源列的數據類型是什麼? –

+0

@ wiz6這是一個語法問題。當您在VBA中編寫SQL語句時,您必須**使用**點**作爲小數點分隔符。你不能寫'0,11' - 你必須寫'0.11' –

2

使用點(「」)作爲小數點分隔符,而不是逗號。

SQL = "UPDATE Table SET field=0.11 WHERE id=12456" 

如果你正在構建的SQL命令,爲了將數字轉換爲字符串使用Str$。它始終使用.作爲小數點分隔符,並且不依賴區域設置。另一方面,Format$函數使用Windows區域設置(可能是逗號)中定義的小數點分隔符。

SQL = "UPDATE Table SET field=" & Str$(x) & " WHERE id=" & id 
+0

謝謝,簡單又容易! – wiz6

0

您可以使用此功能串聯SQL時要避免這種情況和大多數其他的煩惱:

' Converts a value of any type to its string representation. 
' The function can be concatenated into an SQL expression as is 
' without any delimiters or leading/trailing white-space. 
' 
' Examples: 
' SQL = "Select * From TableTest Where [Amount]>" & CSql(12.5) & "And [DueDate]<" & CSql(Date) & "" 
' SQL -> Select * From TableTest Where [Amount]> 12.5 And [DueDate]< #2016/01/30 00:00:00# 
' 
' SQL = "Insert Into TableTest ([Street]) Values (" & CSql(" ") & ")" 
' SQL -> Insert Into TableTest ([Street]) Values (Null) 
' 
' Trims text variables for leading/trailing Space and secures single quotes. 
' Replaces zero length strings with Null. 
' Formats date/time variables as safe string expressions. 
' Uses Str to format decimal values to string expressions. 
' Returns Null for values that cannot be expressed with a string expression. 
' 
' 2016-01-30. Gustav Brock, Cactus Data ApS, CPH. 
' 
Public Function CSql(_ 
    ByVal Value As Variant) _ 
    As String 

    Const vbLongLong As Integer = 20 
    Const SqlNull  As String = " Null" 

    Dim Sql    As String 
    Dim LongLong  As Integer 

    #If Win32 Then 
     LongLong = vbLongLong 
    #End If 
    #If Win64 Then 
     LongLong = VBA.vbLongLong 
    #End If 

    Select Case VarType(Value) 
     Case vbEmpty   ' 0 Empty (uninitialized). 
      Sql = SqlNull 
     Case vbNull    ' 1 Null (no valid data). 
      Sql = SqlNull 
     Case vbInteger   ' 2 Integer. 
      Sql = Str(Value) 
     Case vbLong    ' 3 Long integer. 
      Sql = Str(Value) 
     Case vbSingle   ' 4 Single-precision floating-point number. 
      Sql = Str(Value) 
     Case vbDouble   ' 5 Double-precision floating-point number. 
      Sql = Str(Value) 
     Case vbCurrency   ' 6 Currency. 
      Sql = Str(Value) 
     Case vbDate    ' 7 Date. 
      Sql = Format(Value, " \#yyyy\/mm\/dd hh\:nn\:ss\#") 
     Case vbString   ' 8 String. 
      Sql = Replace(Trim(Value), "'", "''") 
      If Sql = "" Then 
       Sql = SqlNull 
      Else 
       Sql = " '" & Sql & "'" 
      End If 
     Case vbObject   ' 9 Object. 
      Sql = SqlNull 
     Case vbError   ' 10 Error. 
      Sql = SqlNull 
     Case vbBoolean   ' 11 Boolean. 
      Sql = Str(Abs(Value)) 
     Case vbVariant   ' 12 Variant (used only with arrays of variants). 
      Sql = SqlNull 
     Case vbDataObject  ' 13 A data access object. 
      Sql = SqlNull 
     Case vbDecimal   ' 14 Decimal. 
      Sql = Str(Value) 
     Case vbByte    ' 17 Byte. 
      Sql = Str(Value) 
     Case LongLong   ' 20 LongLong integer (Valid on 64-bit platforms only). 
      Sql = Str(Value) 
     Case vbUserDefinedType ' 36 Variants that contain user-defined types. 
      Sql = SqlNull 
     Case vbArray   ' 8192 Array. 
      Sql = SqlNull 
     Case Else    '  Should not happen. 
      Sql = SqlNull 
    End Select 

    CSql = Sql & " " 

End Function