反序列化錯誤 - 列表和對象

Question

我有一個反序列化問題。以下是錯誤返回：

因爲類型需要JSON對象（例如{「名稱」不能反序列化當前JSON陣列（例如[1,2,3]）轉換成類型「SmartTransportNatif.Stations」：」值「}）來正確地反序列化。

"stations": { 
     "from": [ 
      { 
       "id": "008501120", 
       "name": "Lausanne", 
       "score": 101, 
       "coordinate": { 
        "type": "WGS84", 
        "x": 46.516777, 
        "y": 6.629095 
       }, 
       "distance": null 
      } 
     ], 
     "to": [ 
      { 
       "id": "000000178", 
       "name": "Fribourg", 
       "score": null, 
       "coordinate": { 
        "type": "WGS84", 
        "x": 46.803272, 
        "y": 7.151027 
       }, 
       "distance": null 
      } 
     ] 
    } 

這裏是我的對象進行反序列化：

public class RootObject2 
    { 
     public List<Connection> connections { get; set; } 
     public Station from { get; set; } 
     public Station to { get; set; } 
     public Stations stations { get; set; } 
    } 

public class Stations 
    { 
     [JsonProperty("from")] 
     public List<Station> from { get; set; } 

     [JsonProperty("to")] 
     public List<Station> to { get; set; } 
    } 


    public class Station 
    { 
     public string id { get; set; } 
     public string name { get; set; } 
     public object score { get; set; } 
     public Coordinate coordinate { get; set; } 
     public double distance { get; set; } 
    } 

由於錯誤中提到，它的類型是「

我有一個JSON的這部分從服務器返回站「導致的錯誤，但我不明白什麼是錯的。

任何人都可以幫助我嗎？

在此先感謝

Answer 1

讓我們的工作向後首先，這裏有你的類：

看着這些用心，因爲我有正確映射類型每個屬性，基於在你的json對象上。

public class RootObject 
{ 
    public Stations Stations { get; set; } 
} 

public class Stations 
{ 
    public List<Station> From { get; set; } 
    public List<Station> To { get; set; } 
} 


public class Station 
{ 
    public string Id { get; set; } 
    public string Name { get; set; } 
    public int? Score { get; set; } 
    public Coordinate Coordinate { get; set; } 
    public double? Distance { get; set; } 
} 

public struct Coordinate 
{ 
    public string Type { get; set; } 
    public double X { get; set; } 
    public double Y { get; set; } 
} 

這裏是你的類，構造，使您的期望RootObject的樣本。

var data = new RootObject() 
{ 
    Stations = new Stations() 
    { 
     From = new List<Station>() 
     { 
      new Station() 
      { 
       Id = "008501120", 
       Name = "Lausanne", 
       Score = 101, 
       Coordinate = new Coordinate {Type = "WGS84", X = 46.516777, Y = 6.629095}, 
       Distance = null 
      } 
     }, 
     To = new List<Station>() 
     { 
      new Station() 
      { 
       Id = "000000178", 
       Name = "Fribourg", 
       Score = null, 
       Coordinate = new Coordinate {Type = "WGS84", X = 46.803272, Y = 7.151027}, 
       Distance = null 
      } 
     } 
    } 
}; 

var json = Newtonsoft.Json.JsonConvert.SerializeObject(data); 

你得到的價值是這樣的：

{ 
    "Stations": { 
    "From": [ 
     { 
     "Id": "008501120", 
     "Name": "Lausanne", 
     "Score": 101, 
     "Coordinate": { 
      "Type": "WGS84", 
      "X": 46.516777, 
      "Y": 6.629095 
     }, 
     "Distance": null 
     } 
    ], 
    "To": [ 
     { 
     "Id": "000000178", 
     "Name": "Fribourg", 
     "Score": null, 
     "Coordinate": { 
      "Type": "WGS84", 
      "X": 46.803272, 
      "Y": 7.151027 
     }, 
     "Distance": null 
     } 
    ] 
    } 
} 

這個工作在反向罰款。

var foo = Newtonsoft.Json.JsonConvert.DeserializeObject<RootObject>(json); 

---

證明它的工作原理根據您的鏈接

http://transport.opendata.ch/v1/connections?from=lausanne&to=fribourg
以上，這裏都在行動

var httpWebRequest = (HttpWebRequest)WebRequest 
    .Create("http://transport.opendata.ch/v1/connections?from=lausanne&to=fribourg"); 
httpWebRequest.ContentType = "application/json"; 
httpWebRequest.Method = "GET"; 
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse(); 

using (var streamReader = new StreamReader(httpResponse.GetResponseStream())) 
{ 
    var result = streamReader.ReadLine(); 
    var foo = Newtonsoft.Json.JsonConvert.DeserializeObject<RootObject>(result); 
} 

工作正常類。

---

你的錯誤消息

您得到的誤差：

無法反序列化當前JSON陣列（例如[1,2,3]）轉換成類型「SmartTransportNatif.Stations '，因爲該類型需要一個JSON對象（例如{「name」：「value」}）來正確反序列化。

這指向一個你甚至沒有在你的問題中顯示的類，它只是被錯誤地建模爲json。但是因爲它不是與你的問題一起提供的，所以上面的答案足以顯示出錯的地方。

Answer 2

我假設你缺少在前面，並在年底{}。如果是的話，下面的檢查：從它

public class Coordinate 
{ 
    public string type { get; set; } 
    public double x { get; set; } 
    public double y { get; set; } 
} 

public class From 
{ 
    public string id { get; set; } 
    public string name { get; set; } 
    public int score { get; set; } 
    public Coordinate coordinate { get; set; } 
    public object distance { get; set; } 
} 

public class Coordinate2 
{ 
    public string type { get; set; } 
    public double x { get; set; } 
    public double y { get; set; } 
} 

public class To 
{ 
    public string id { get; set; } 
    public string name { get; set; } 
    public object score { get; set; } 
    public Coordinate2 coordinate { get; set; } 
    public object distance { get; set; } 
} 

public class Stations 
{ 
    public List<From> from { get; set; } 
    public List<To> to { get; set; } 
} 

public class RootObject 
{ 
    public Stations stations { get; set; } 
}