追蹤動畫球

Question

在這個項目中，我試圖追蹤一個球。如果球的顏色是灰色的，我希望它被正方形包圍。我的問題是隻有一個球被追蹤。我想要追蹤所有的灰色球。

如果有人能幫助我，我會非常感激。

下面是代碼（球和Box從外部類的稱呼）：你需要把你的支票顏色在for循環檢查所有的球

package { 

import flash.display.Sprite; 
import flash.events.Event; 
import flash.geom.Point; 

[SWF(frameRate='31')] 

    public class Main extends Sprite 
    { 

     private var balls:Array; 
     private var directions:Array = [new Point(-1,-1),new Point(0,-1),new Point(1,-1), 
             new Point(-1,0),new Point(1,0), 
             new Point(-1,1),new Point(0,1),new Point(1,1) 
             ]; 

     private var ballNum: Number = 10; 
     private var ball:Ball; 
     private var ball2:Ball; 
     private var box:Box; 

     private var ay:Number = 5; 
     private var gravity:Number = 6; 
     private var bounce:Number = -0.9; 

     public function Main() 
     { 
      init(); 
     } 
     private function init():void 
     { 
      balls = new Array(); 

      for(var i:Number = 0; i < ballNum; i++) 
      { 
       ball = new Ball(Math.random() * 30); 
       ball.x = Math.random() * stage.stageWidth; 
       ball.y = Math.random() * stage.stageHeight; 
       ball.direction = directions[Math.floor(Math.random()*directions.length)]; 
       addChild(ball); 

       balls.push(ball); 
      } 

      box = new Box(); 
      addChild(box); 

      addEventListener(Event.ENTER_FRAME, onEnterFrame); 
     } 

     private function onEnterFrame(event:Event):void 
     { 
      for(var i:int = 0; i < balls.length; i++) 
      { 
       balls[i].x += balls[i].direction.x; 
       balls[i].y += balls[i].direction.y; 
      } 
      if(ball.color == 0xcccccc) 
      { 
       box.x = ball.x - box.width/2; 
       box.y = ball.y - box.height/2; 
      } 
     } 
    } 
} 

Answer 1

：

for (var i: int = 0; i < balls.length; i++) { 
    balls[i].x += balls[i].direction.x; 
    balls[i].y += balls[i].direction.y; 

    if (balls[i].color == 0xcccccc) { 
     box.x = balls[i].x - box.width/2; 
     box.y = balls[i].y - box.height/2; 
    } 
} 

Answer 2

在onEnterFrame函數結束後，只有一個框和一個框只能有一個x和y。

嘗試這樣的事：

for (var i: int = 0; i < balls.length; i++) { 
    balls[i].x += balls[i].direction.x; 
    balls[i].y += balls[i].direction.y; 

    if (balls[i].color == 0xcccccc) { 
     box[i].x = balls[i].x - box[i].width/2; 
     box[i].y = balls[i].y - box[i].height/2; 
     //OR balls[i].box.visible=true; 
    } 
}