-1
我使用這個代碼:處理參數++不工作
int handleArgs(int argc, char *argv[]) {
if(argc <= 1)
{return 0;}
else
{ // If no arguments, terminate, otherwise: handle args
for(int i=1; i<argc; i++) {
if (argv[i] == "-a" || argv[i] == "--admin")
{ // If admin argument
char *pwd = argv[i+1]; // i + 1 b/c we want the next argument; the password
if(pwd == "1729" || pwd == "GabeN")
{ // Verify Password
cout << "Sorry, console feature unavailable.\n" << endl;// Will replace with console function when I get to it
}
else
{
cout << "Wrong/No passkey, bruh.\n" << endl;
} // If the password is wrong
}
else if (argv[i] == "-v" || argv[i] == "--version")
{ // If user asks for version info
cout << "You are running\nDev0.0.0" << endl; // Tell the user the version
}
else if (argv[i]==" -h" || argv[i]=="--help")
{
cout << "Usage: " << argv[0] << " -[switch] argument(s)\n";
cout << " -a, --admin Open console view. Requires password\n";
cout << " -v, --version Print version and exit\n";
cout << " -h, --help Print this message and exit\n" << endl;
}
else {
cout << "Is you dumb?\n '" << argv[0] << " --help' for help" << endl; // Insult the user
}
}
}
return 1;
}
然而,每次我給它一個說法,我收到無效的參數消息(最後else語句):
Is you dumb?
'main --help' for help
我是C++的新手,我不知道我在做什麼(錯誤)。任何人都可以提供一些有用的見解嗎?感謝
--FracturedCode
你能告訴我你是如何傳遞參數...僅供參考.. –
@MGP int main(int argc,char * argv []) – Gabe
@MGP handleArgs(argc,argv); – Gabe