基本上我使用了Firefox擴展來獲取帖子並從登錄頁面獲取數據到我的學校網站。我希望能夠登錄,但當我嘗試它時說「會話過期請重新登錄!」。這是我迄今爲止的代碼,誰能告訴我我做錯了什麼?我認爲這與重定向有關,因爲第一篇文章應該重定向到正確的位置,但我不能讓它工作,並試圖獲取位置標題將引發空指針。使用android登錄網站
try {
super.onCreate(icicle);
CookieManager cookieManager = new CookieManager();
CookieHandler.setDefault(cookieManager);
BasicClientCookie netscapeCookie = new BasicClientCookie("UserLoginInfo", "SelectedTab=StudentLogin&RedirectURL=");
netscapeCookie.setVersion(0);
netscapeCookie.setDomain("sisk12.hannibal.k12.mo.us");
netscapeCookie.setPath("/");
cookieStore.addCookie(netscapeCookie);
localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);
HttpPost httpost = new HttpPost("https://sisk12.hannibal.k12.mo.us/hb/Default.aspx?__EVENTTARGET=&__EVENTARGUMENT=&txtUserName=xxxx&txtPassword=xxxxxx&btnLogin=Login&txtSelectedTab=StudentLogin");
HttpResponse response = httpclient.execute(httpost, localContext);
HttpEntity entity = response.getEntity();
// readResponse(response.getEntity().getContent());
//Log.w("****","Login form get: " + response.getFirstHeader("Location").getValue());
// readResponse(response.getEntity().getContent());
if (entity != null) {
entity.consumeContent();
}
Header[] headers = response.getHeaders("Location");
if (headers != null && headers.length != 0) {
String newUrl = headers[headers.length - 1].getValue();
// call again with new URL
HttpGet httpget = new HttpGet(newUrl);
entity = response.getEntity();
Log.w("****", "Login form get: " + response.getStatusLine());
response = httpclient.execute(httpget, localContext);
readResponse(response.getEntity().getContent());
} else {
Log.w("****", "No location header");
}
if (cookieStore.getCookies().isEmpty()) {
Log.w("****", "None");
} else {
for (int i = 0; i < cookieStore.getCookies().size(); i++) {
Log.w("****", "- " + cookieStore.getCookies().get(i).toString());
}
}
// When HttpClient instance is no longer needed,
// shut down the connection manager to ensure
// immediate deallocation of all system resources
httpclient.getConnectionManager().shutdown();
} catch (IOException ex) {
Log.e("****", Log.getStackTraceString(ex));
}
public String readResponse(InputStream input) throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(input));
StringBuilder sb = new StringBuilder("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line).append(NL);
}
in.close();
String page = sb.toString();
Log.i("****", page);
return page;
}
更新
我改變了我的代碼,並得到這個響應 - 發生了下列錯誤
錯誤消息:未能http請求開始! 技術消息:線程正在中止。 調用堆棧:_pvt_ApplicationBeginRequestParameter列表:現在
我的代碼是
static String regex ="name=\"__VIEWSTATE\" value=\"";
String getURL = "https://sisk12.hannibal.k12.mo.us/hb/Default.aspx";
String postURL = getURL;
DefaultHttpClient client = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpGet getMethod = new HttpGet(getURL);
HttpResponse response = client.execute(getMethod, localContext);
String getString=readResponse(response.getEntity().getContent());
int start = getString.indexOf(regex)+regex.length();
String viewState = getString.substring(start, getString.indexOf('"', start+1));
Log.i("****", viewState);
HttpPost postMethod = new HttpPost(postURL);
postMethod.addHeader("__EVENTARGUMENT", "");
postMethod.addHeader("__EVENTTARGET", "");
postMethod.addHeader("__VIEWSTATE", viewState); //to be parsed from login page
postMethod.addHeader("btnLogin", "Login");
postMethod.addHeader("txtPassword", "xxxxxx");
postMethod.addHeader("txtSelectedTab", "StudentLogin");
postMethod.addHeader("txtUserName", "xxxx");
HttpResponse postResponse = client.execute(postMethod, localContext);
String postString = readResponse(postResponse.getEntity().getContent());
Log.w("****", postString);
HttpGet getGrades = new HttpGet("https://sisk12.hannibal.k12.mo.us/hb/Portal/Parent/ParentLogin.aspx");
HttpResponse response2 = client.execute(getGrades, localContext);
String getGradesString=readResponse(response2.getEntity().getContent());
Log.i("****", getGradesString);
存在應由後調用代碼中的重定向,但我不如果Apache自動完成這個功能或不是以及如何處理,如果不是?
您是否設置了httpclient來處理https請求(而不是http)?無論如何, – kingori
,請在該網址中刪除您的ID和密碼。 – kingori
我不確定如果我沒有用戶名並且通過但我現在刪除了他們,我會得到任何幫助。這讓我有點緊張,把他們放在網上 – ghostbust555