從開始日期和結束日期分割開始日期和結束日期不適用於不同的星期

Question

需要查找週末，週六和週日以及其他平日的總分鐘時間。 使用下面的一段代碼，但它不會產生所需的結果。

$start_day = date('w', $start_time); 
     $start_hour = date('G', $start_time); 
     $end_day = date('w', $end_time); 
     $end_hour = date('G', $end_time); 
     $normal_hours = $surge_hours = 0; 


     for (;($start_hour < 24 && $start_day <= $end_day); $start_hour++) { 

      switch ($start_day) { 
       case 0: $surge_hours++; 
        break; 
       case 5: $surge_hours++; 
        break; 
       case 6: $surge_hours++; 
        break; 
       case 1: $normal_hours++; 
        break; 
       case 2: $normal_hours++; 
        break; 
       case 3: $normal_hours++; 
        break; 
       case 4: $normal_hours++; 
        break; 
      } 
      echo __line__; 
      echo "<pre>"; 
      print_r('surgehours'.$surge_hours); 
      echo "<br/>"; 
      print_r('normalhours'.$normal_hours); 
      echo "<pre/>"; 
      if ($start_hour == 23) { 
       $start_hour = 0; 
       $start_day++; 
      } 

      if ($start_day == $end_day) { 
       if ($start_hour == $end_hour) 
        break; 
      } 
     } 

失敗問題的用例：

如果開始一天是星期五，即：7月29日和結束日爲8月1日（$start_day = 5 and $end_day = 1）
它不會進入循環。

任何想法如何計算小時？

Answer 1

新的代碼如下（清理了，改變了比較運算符<，而不是< =這阻止去年增了一小時，從未來通過）：

<?php 
$start_time = strtotime('next friday 11am'); 
$end_time = $start_time + (60*60*24*3); 

function allocate_hour($timestamp) { 
    if(date('w',$timestamp) >= 5 OR date('w',$timestamp) == 0) { 
     return 0; 
    } else { return 1; } 
} 

$weekdayhours = 0; 
$weekendhours = 0; 
for($thistime=$start_time;$thistime<$end_time;$thistime+=3600){ 
    if(allocate_hour($thistime) === 1) { $weekdayhours++; } else { $weekendhours++; } // add 1 for each hour. 
} 

echo 'Weekday hours: '.$weekdayhours; 
echo '<BR>weekend hours: '.$weekendhours; 

Answer 2

不是很漂亮的代碼，但它的工作原理：

注：日期由年有限

<?php 

// test values 
$start_date = mktime(9,0,0,5,5,2016); // 5-may-2016 (Thursday) 
$end_date = mktime(18,0,0,5,20,2016); // 20-may-2016 (Saturday) 

// count days between dates 
$days_between = date('z',$end_date) - date('z', $start_date) + 1; 
// guessing how many weekends days can be 
$weekdays = floor($days_between/7)*3; 

// get weekday nubmer 1-monday..7-sunday 
$sday = date('N',$start_date); 
$eday = date('N',$end_date); 

// initialize counters 
$surge = 0; 
$normal = 0; 

if ($days_between >=7) { 
    // correct weekends days count 
    // when we have more than 1 week difference 
    switch ($sday) { 
     case 7: 
      $weekdays--; 
     case 6: 
      $weekdays--; 
    } 

    switch ($eday) { 
     case 7: 
      $weekdays++; 
     case 6: 
      $weekdays++; 
     case 5: 
      $weekdays++; 
    } 
} else { 
    // correct weekends days count 
    // when we have less than 1 week difference 
    switch ($sday) { 
     case 1: 
     case 2: 
     case 3: 
     case 4: 
     case 5: 
      $weekdays++; 
     case 6: 
      $weekdays++; 
     case 7: 
      $weekdays++; 
    } 
    switch ($eday) { 
     case 5: 
      $weekdays--; 
     case 6: 
      $weekdays--; 
    } 
} 

// remember start and end hours 
$shour = date('G', $start_date); 
$ehour = date('G', $end_date); 

if ($sday == $eday) { 
    // we're start and end at the same day 
    if (in_array($sday, array(5,6,7))) { 
     $surge += $ehour - $shour; 
    } else { 
     $normal += $ehour - $shour; 
    } 
} else { 
    $first_day_hours = 24 - $shour; 
    $last_day_hours = $ehour; 
    // decrease counter by two, because 
    // the first and last days process separately 
    $days_between -= 2; 

    if (in_array($sday, array(5,6,7))) { 
     $surge += $first_day_hours; 
     $weekdays--; 
    } else { 
     $normal += $first_day_hours; 
    } 

    if (in_array($eday, array(5,6,7))) { 
     $surge += $last_day_hours; 
     $weekdays--; 
    } else { 
     $normal += $last_day_hours; 
    } 

    if ($days_between>0) { 
     $surge += 24 * $weekdays; 
     $normal += 24 * ($days_between - $weekdays); 
    } 
} 


echo 'Normal: '.$normal.PHP_EOL; 
echo ' Surge: '.$surge.PHP_EOL; 

代碼接近信號源（使用循環）：

注：日期不限

<?php 

// test values 
$start_date = mktime(9,0,0,5,5,2016); 
$end_date = mktime(18,0,0,5,20,2016); 

// remember start and end hours 
$shour = date('G', $start_date); 
$ehour = date('G', $end_date); 
$first_day_hours = 24 - $shour; 
$last_day_hours = $ehour; 

$sdate = mktime(0,0,0,date('m',$start_date),date('d',$start_date)+1,date('Y',$start_date)); 
$edate = mktime(0,0,0,date('m',$end_date),date('d',$end_date)-1,date('Y',$end_date)); 

// initialize counters 
$surge = 0; 
$normal = 0; 

if (in_array(date('N',$start_date), array(5,6,7))) { 
    $surge += $first_day_hours; 
} else { 
    $normal += $first_day_hours; 
} 
if (in_array(date('N',$end_date), array(5,6,7))) { 
    $surge += $last_day_hours; 
} else { 
    $normal += $last_day_hours; 
} 
while ($sdate<=$edate) { 
    if (in_array(date('N',$sdate), array(5,6,7))) { 
     $surge += 24; 
    } else { 
     $normal += 24; 
    } 
    $sdate = mktime(0,0,0,date('m',$sdate),date('d',$sdate)+1,date('Y',$sdate)); 
} 
echo 'Normal: '.$normal.PHP_EOL; 
echo ' Surge: '.$surge.PHP_EOL;