重新分配二維數組的值

Question

編輯：謝謝大家誰幫助我瞭解我必須做什麼和問題是什麼。

SudokuStuff接口

public interface SudokuStuff 
{ 
    int[][] sudokuGrid = new int[][] {{2,4,0,6,8,0,3,0,0}, 
      {0,0,0,0,0,0,9,0,0}, 
      {6,5,0,0,1,0,0,8,7}, 
      {0,0,0,0,0,7,0,9,8}, 
      {9,3,2,5,0,8,7,1,4}, 
      {7,1,0,4,0,0,0,0,0}, 
      {4,9,0,0,7,0,0,2,5}, 
      {0,0,5,0,0,0,0,0,0}, 
      {0,0,1,0,4,5,0,7,3}}; 
    void addNumber(int x, int y, int value); 
    void removeNumber(int x, int y); 
    void resetGrid(); 
    void drawGrid(); 
} 

數獨類

public class Sudoku implements SudokuStuff{ 

    public void drawGrid(){ 
     System.out.println(" ----- ----- ----- "); 
     for(int i = 0; i < 9; i++){ 
      if(i==3||i==6){ 
       System.out.println(" ----- ----- ----- "); 
      } 
      for(int j = 0; j < 9; j++){ 
       if(j==0||j==3||j==6){ 
        System.out.print(" |"); 
       } 
       if(sudokuGrid[i][j] != 0){ 
        System.out.print(" "+sudokuGrid[i][j]); 
       } else{ 
        System.out.print(" "); 
       } 
       if(j==8){ 
        System.out.print(" |"); 
       } 
      } 
      System.out.println(); 
     } 
     System.out.println(" ----- ----- ----- "); 
    } 

    public void addNumber(int x, int y, int value){ 
     if(x>9||x<1||y>9||y<1||value>9||value<0){ 
      System.out.println("Bad Input"); 
     }else{ 
      sudokuGrid[x-1][y-1] = value; 
     } 
     drawGrid(); 
    } 

    public void removeNumber(int x, int y){ 
     if(x>9||x<1||y>9||y<1){ 
      System.out.println("Bad Input"); 
     }else{ 
      sudokuGrid[x-1][y-1] = 0; 
     } 
     drawGrid(); 
    } 
    public void resetGrid(){ 
     sudokuGrid = {{2,4,0,6,8,0,3,0,0}, 
      {0,0,0,0,0,0,9,0,0}, 
      {6,5,0,0,1,0,0,8,7}, 
      {0,0,0,0,0,7,0,9,8}, 
      {9,3,2,5,0,8,7,1,4}, 
      {7,1,0,4,0,0,0,0,0}, 
      {4,9,0,0,7,0,0,2,5}, 
      {0,0,5,0,0,0,0,0,0}, 
      {0,0,1,0,4,5,0,7,3}}; 
     drawGrid(); 
    } 
} 

所以讓我的問題，在SudokuStuff我有一個2D與預設值，在數獨我有一個resetGrid方法不工作。正如你所看到的，我希望它將網格重置爲原始形式。有關這樣做的任何建議？我現在擁有的表達錯誤非法開始。

如果你知道答案，還有一個附註，有沒有什麼辦法可以在交互窗格中從SudokuStuff的Sudoku中運行方法。這是我的中期練習題，並且仍然與界面事物混淆。

任何幫助將不勝感激，如果我不立即回答它的可能是因爲我昏昏欲睡，因爲它晚了很晚在這裏。謝謝。

Answer 1

字段是static和final（更不用說public），換句話說，它們是意味着你不能重新分配他們的常量。

如果你希望能夠像做

public void resetGrid(){ 
    sudokuGrid = new int[][]{ 
     {2,4,0,6,8,0,3,0,0}, 
     {0,0,0,0,0,0,9,0,0}, 
     {6,5,0,0,1,0,0,8,7}, 
     {0,0,0,0,0,7,0,9,8}, 
     {9,3,2,5,0,8,7,1,4}, 
     {7,1,0,4,0,0,0,0,0}, 
     {4,9,0,0,7,0,0,2,5}, 
     {0,0,5,0,0,0,0,0,0}, 
     {0,0,1,0,4,5,0,7,3} 
    }; 
    drawGrid(); 
} 

你應該在你的類int[][] sudokuGrid場。

編輯：

如果陣列在接口中聲明，那麼你可以嘗試重新分配其行（他們是不是最終的）。這裏是你如何做到這一點的例子：

public void resetGrid(){ 
    int[][] tmp = { 
     {2,4,0,6,8,0,3,0,0}, 
     {0,0,0,0,0,0,9,0,0}, 
     {6,5,0,0,1,0,0,8,7}, 
     {0,0,0,0,0,7,0,9,8}, 
     {9,3,2,5,0,8,7,1,4}, 
     {7,1,0,4,0,0,0,0,0}, 
     {4,9,0,0,7,0,0,2,5}, 
     {0,0,5,0,0,0,0,0,0}, 
     {0,0,1,0,4,5,0,7,3} 
    }; 
    for (int i=0; i<sudokuGrid.length; i++) 
     sudokuGrid[i]=tmp[i]; 
    drawGrid(); 
} 

Answer 2

重置函數不起作用的原因是您在resetGrid函數中聲明瞭一個具有相同名稱的新變量，而不是將所需的值分配給類級變量。拿走sudokuGrid上的類型，它應該工作。

Answer 3

您需要new int[][]這樣：

sudokuGrid = new int[][] {...}; 

我不認爲它甚至編譯否則（？）。聲明變量時只能使用= {...}，而不能重新指定變量。

決賽：評論後

public void resetGrid(){ 
    sudokuGrid = new int[][] {{2,4,0,6,8,0,3,0,0}, 
     {0,0,0,0,0,0,9,0,0}, 
     {6,5,0,0,1,0,0,8,7}, 
     {0,0,0,0,0,7,0,9,8}, 
     {9,3,2,5,0,8,7,1,4}, 
     {7,1,0,4,0,0,0,0,0}, 
     {4,9,0,0,7,0,0,2,5}, 
     {0,0,5,0,0,0,0,0,0}, 
     {0,0,1,0,4,5,0,7,3}}; 
} 

編輯：

好的編輯完全把我的頭頂部沒有真正去想它。有「默認」的靜態最終陣列，並用它來重置數組修改：

static final int[][] defaultGrid = new int[][] {{2,4,0,6,8,0,3,0,0}, 
     {0,0,0,0,0,0,9,0,0}, 
     {6,5,0,0,1,0,0,8,7}, 
     {0,0,0,0,0,7,0,9,8}, 
     {9,3,2,5,0,8,7,1,4}, 
     {7,1,0,4,0,0,0,0,0}, 
     {4,9,0,0,7,0,0,2,5}, 
     {0,0,5,0,0,0,0,0,0}, 
     {0,0,1,0,4,5,0,7,3}}; 

... 

// This will reset the grid to whatever is in defaultGrid 
// assuming they have the same lengths 
for (int i = 0; i = sudokuGrid.length; i++) { 
    for (int y = 0; y = sudokuGrid[y].length; y++) { 
     sudokuGrid[i][y] = defaultGrid[i][y]; 
    } 
} 

Answer 4

你要碰到的問題是在接口中聲明的變量基本上是最後的。你可以做一些不同的事情，但最簡單的做法是在數獨中創建一個變量，通過在運行時將sudokuGrid克隆到其中，並在重置時通過再次重新分配sudokuGrid來重置它。在接口中聲明