-2
我有以下函數可以從數據庫中獲取與作業相關的一些數據。用戶可以搜索職位/關鍵字,城市和/或類別。用戶可以選擇一個選項,例如僅按職位或類別搜索職位。或者他可以使用所有選項進行深度搜索。以下是我的功能:在laravel中寫入函數
public function jobsearch(Request $request)
{
$keyword = htmlspecialchars($request->input('keyword'));
$city_id = $request->input('city_id');
$category_id = $request->input('category_id');
if($keyword !== '' && $city_id != 0 && $category_id == 0)
{
$data = DB::table('job_details')->where('job_title', 'like', '%'.$keyword.'%')->where('city_id', $city_id)->get();
}
elseif($keyword !== '' && $city_id == 0 && $category_id != 0)
{
$data = DB::table('job_details')->where('job_title', 'like', '%'.$keyword.'%')->where('category_id', $category_id)->get();
}
elseif($keyword == '' && $city_id != 0 && $category_id != 0)
{
$data = DB::table('job_details')->where('category_id', $category_id)->where('city_id', $city_id)->get();
}
elseif($keyword !== '' && $city_id == 0 && $category_id == 0)
{
$data = DB::table('job_details')->where('job_title', 'like', '%'.$keyword.'%')->get();
}
elseif($keyword == '' && $city_id == 0 && $category_id != 0)
{
$data = DB::table('job_details')->where('category_id', $category_id)->get();
}
elseif($keyword == '' && $city_id != 0 && $category_id == 0)
{
$data = DB::table('job_details')->where('city_id', $city_id)->get();
}
else
{
$data = DB::table('job_details')->where('job_title', 'like', '%'.$keyword.'%')->where('category_id', $category_id)->where('city_id', $city_id)->get();
}
foreach($data as $data)
{
echo $data->job_title.'<br>';
}
}
正如你所看到的,這個函數對許多if和elseif語句來說太亂了。我的問題是,如果有什麼方法可以用乾淨的方式編寫給定的函數?你會如何在你的風格中編寫給定的功能?請幫忙。
@Rishi是的,複製/粘貼故障。我編輯過。 – ceejayoz