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我想打電話給在RestKit RKRoute這種方法迅速(類):如何調用xxxxWithClass:在迅速
+ (instancetype)routeWithClass:(Class)objectClass pathPattern:(NSString *)pathPattern method:(RKRequestMethod)method;
但我發現我不能用「階級」作爲參數的標籤,編譯器處理它作爲關鍵字
var route:RKRoute = RKRoute(class: Article.self, pathPattern: "/categories/:comment.name/articles/:articleID/comments/", method:RKRequestMethod.GET)
如何調用它?