-1
我正在嘗試將Google地圖嵌入到我的網頁中,並使用鏈接到不同網站的標籤。我將如何去做這件事? 供圖這是我的源代碼至今:嵌入的谷歌地圖與鏈接到網頁的針腳
<script type="text/javascript">
var locations = [
['Bondi Beach', -33.890542, 151.274856, 4, "google.com"],
['Coogee Beach', -33.923036, 151.259052, 5],
['Cronulla Beach', -34.028249, 151.157507, 3],
['Manly Beach', -33.80010128657071, 151.28747820854187, 2],
['Maroubra Beach', -33.950198, 151.259302, 1]
];
var map = new google.maps.Map(document.getElementById('map'), {
zoom: 10,
center: new google.maps.LatLng(-33.92, 151.25),
mapTypeId: google.maps.MapTypeId.ROADMAP
});
var infowindow = new google.maps.InfoWindow();
var marker, i;
for (i = 0; i < locations.length; i++) {
marker = new google.maps.Marker({
position: new google.maps.LatLng(locations[i][1], locations[i][2]),
map: map,
url: locations[i][3],
});
google.maps.event.addListener(marker, 'click', (function(marker, i) {
return function() {
infowindow.setContent(locations[i][0]);
infowindow.open(map, marker);
}
})(marker, i));
}
</script>
我仍然不能得到URL時,我上的標記點擊工作。請參閱上面編輯過的帖子。 –
將http或https添加到我的末尾並將網址設置爲位置[i] [4] – Jack
我不知道我在做什麼錯誤,但該網址仍然無效。這是不正確的?當我評論代碼時,http會消失,但鏈接是「http://google.com」。代碼:var locations = [ ['Bondi Beach',-33.890542,151.274856,4,「http://google.com」], ['Coogee Beach',-33.923036,151.259052,5], ['Cronulla Beach',-34.028249,151.157507,3], ['Manly Beach',-33.80010128657071,151.28747820854187,2], ['Maroubra Beach',-33.950198,151.259302,1] –