的XPath檢索兩個查詢

Question

我想要從本網頁上的「課程負責人的姓名和電子郵件地址：

http://www.westminster.ac.uk/schools/computing/undergraduate/computer-games-development/bsc-honours-computer-games-development。

這怎麼可能實現？

我試圖找回後「課程內容」第一<p>，但犯規相當的工作..

"//div[starts-with(@id,'content_div')]/h3[.='Course Content']/following-sibling::p[1] 

Answer 1

我不知道到底是什麼XML/XPath的代碼看起來像在Objective C，但我懷疑你是已經得到你需要的所有信息，你只需要做更多的事情就可以把它分開。您的XPath檢索節點看起來是這樣的（我已經編輯內容）：

<p>Anastassia Angelopolou<br /> 
Email: <a href="mailto:agelopa@wmin.ac.uk.invalid">agelopa@wmin.ac.uk.invalid</a></p> 

所以，如果你只是問了p節點的文本，你剛纔得到的文本Anastassia Angelopolou，（第一）內文本直到第一個子節點（<br />）。要獲取電子郵件地址，您可以從p節點xpath到./a子節點，並採用文本或@href的值。

Answer 2

由於您正在尋找的值中沒有真正唯一的標識標籤，我會跳過xpath並創建一個骯髒的小黑客。

// get the HTML code. 
NSString * getURL = [NSString stringWithFormat:@"http://www.westminster.ac.uk/schools/computing/undergraduate/computer-games-development/bsc-honours-computer-games-development"]; 
NSData * htmlData = [[NSData alloc] initWithContentsOfURL:[NSURL URLWithString:getURL]]; 
NSString *htmlString = [[NSString alloc] initWithData:htmlData encoding:NSUTF8StringEncoding]; 


//seperate the HTML code by the unique HTML line of "<h3>Course Leader</h3>" 
NSArray *tempArray = [htmlString componentsSeparatedByString:@"<h3>Course Leader</h3>"]; 
NSString * tempString1 = [[tempArray objectAtIndex:1]description]; 

//get Name 
NSArray * tempArray2 = [tempString1 componentsSeparatedByString:@"<br />"]; 

//set name 
NSString * nameString = [[tempArray2 objectAtIndex:0]description]; 
//clean up name string 
nameString = [nameString stringByReplacingOccurrencesOfString:@"\n" withString:@""]; 
nameString = [nameString stringByReplacingOccurrencesOfString:@"\r" withString:@""]; 
nameString = [nameString stringByReplacingOccurrencesOfString:@"<p>" withString:@""]; 

//get Email 
NSArray * emailArray = [tempString1 componentsSeparatedByString:@">"]; 

//set email string 
NSString * emailString = [[emailArray objectAtIndex:3]description]; 
//clean up email string 
emailString = [emailString stringByReplacingOccurrencesOfString:@"</a" withString:@""]; 

NSLog(@"Results: Name = %@ Email = %@",nameString,emailString);