如果字段匹配，則更新並刪除

Question

我明白，在沒有任何工作要顯示的情況下提出問題有點粗魯，但是我有點難倒，需要一些幫助。

我需要從一個MySQL表中刪除行，如果在另一個表中的另一個領域是等於1

我有兩個表table_1和table_2

table_1有兩個字段location和events

並且table_2具有被稱爲location的字段，其與location相同table_1

我想刪除table_2一行或多行，如果場location相同table_1和events = 1

類似：

if `events` = 1 in `table_1` in 'location' `*`; 
    delete row(s) from `table_2` 
    where `location` is the same as `location` in `table_1` 

Answer 1

DELETE t2 
    FROM `table2` t2 
    JOIN `table1` t1 ON t1.events = 1 
        AND t1.location = t2.location 

Answer 2

試試這個：

delete from `table_2` 
    where location in (select location from `table_1` where events=1) 

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編輯

DELETE t2 FROM `table_2` t2 
    JOIN `table_1` t1 ON t1.location = t2.location where t1.events=1