我有簡單的PHP頁面腳本,我從DB顯示數據
獲取數據$plot_row1 = array();
$plot_row2 = array();
$query1 = "SELECT date, name, value FROM list WHERE date between '$s_date' and '$e_date'
ORDER BY date";
$result = $mysqli->query($query1);
while ($row = $result->fetch_array(MYSQL_ASSOC))
{
$sum_list = $sum_list + $row['value'];
$plot_row1[] = $row['value'];
$plot_row2[] = $row['date'];
}
然後我想有jqplot圖表,其中X軸從$ plot_row2 [],由日期Y軸包含從$ plot_row2 []
我開始與下面的代碼,我需要的是以某種方式準備值(在PHP中)以適當的方式作爲jqplot的輸入(而不是問號)。
echo "<div id='loggerChart1' style='height:400px;width:400px;'>";
echo "<script class='code' type='text/javascript' language='javascript'>";
echo "$.jqplot('loggerChart1', [?????]);";
echo "</script>";
echo "</div>";
謝謝
而準備的數據將如何?逗號分隔的字符串/數字? – djot