嘗試重新創建我的console.log對象

Question

我有一個var，它包含我在控制檯中註銷時看到的4個對象。但是我一直試圖創建這個返回變量的結構（我想對它進行排序，但首先要重新創建結構），但是在最後一個障礙中失敗。

這是控制檯推出的原變量：[Object, Object, Object, Object]

這是我得到創建變量：[Object]

這裏是我的代碼，試圖重新創建它：

this.obj =  [{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
          {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
        color:'blue'}], 
        [{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
          {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
        color:'green'}], 
        [{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
          {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
        color:'red'}], 
        [{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
          {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
        color:'yellow'}] 
        ; 

的兩個原始的第一對象d 創建的是相同的，但爲什麼它看不到我的其他三個對象？如果我添加兩個[]在我的代碼，它認爲所有的四個，但後來他們改變了對數組而不是對象...

Answer 1

得到它的人誰想要知道的工作：

this.obj =  [{0:{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
         {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
       color:'blue'}}, 
       {1:{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
         {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
       color:'green'}}, 
       {2:{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
         {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
       color:'red'}}, 
       {3:{items:[{code:'bravo',color:'blue',date:'2017-01-01',pos:'up'}, 
         {code:'alpha',color:'blue',date:'2017-01-02',pos:'down'}], 
       color:'yellow'}}] 
       ; 
} 

Answer 2

你的代碼似乎打破，如果你在一個可讀方式訂購它，然後很清楚：然後

var obj = [ 
    { 
     items: [{ 
      code: 'bravo', color: 'blue', date: '2017-01-01', pos: 'up' 
     }, { 
      code: 'alpha', color: 'blue', date: '2017-01-02', pos: 'down' 
     }], 
     color: 'blue' 
    }] // <=== the array ends here, but now you have this: 
    , [{ items: [{ ... 

編譯器做到這一點：

var obj = [ 
    { 
     items: [{ 
       code: 'bravo', color: 'blue', date: '2017-01-01', pos: 'up' 
      }, { 
       code: 'alpha', color: 'blue', date: '2017-01-02', pos: 'down' 
      }], 
     color: 'blue' 
    } 
], _a = (void 0)[0], _b = .... 

正如你可以看到它創建了另一個變量（_a）來存儲的其他數據。