錯誤Matlab代碼

Question

約分頻段編碼

餘碼，並且延遲信號 我的代碼：

N = 18; %Setting the filter length 
[h0,h1,g0,g1] = firpr2chfb(N-1,0.4); % MATLAB function for the analysis/synthesis  
num=20000; 
[x,fs,nbits] = wavread('sub1.wav',num); 
% Analysis part 
% Level 1 
x0 = filter(h0,1,x); % Lowpass filtering 
x1 = filter(h1,1,x); % Highpass filtering 
v0 = downsample(x0,2); % Down-sampling, signal component v_0[n] 
v1= downsample(x1,2); % Down-sampling, signal component v_1[n] 
% Level 2 
x2= v0; % Selecting the lowpass output from Level for the input to Level 
x02 = filter(h0,1,x2); % Lowpass filtering 
x12 = filter(h1,1,x2); % Lowpass filtering 
v02= downsample(x02,2); % Down-sampling 
v12= downsample(x12,2); % Down-sampling 
v2= v12; % Signal component v_2[n] 
% Level 3 
x3= v02; % Selecting the lowpass output from Level for the input to Level 
x03 = filter(h0,1,x3); % Lowpass filtering 
x13 = filter(h1,1,x3); % Highpass filtering 
v03= downsample(x03,2); % Down-sampling 
v13= downsample(x13,2); % Down-sampling 
v3= v13; % Signal component v_3[n] 
w13= [zeros(size(1:N-1)) v3(1:length(v3)-(N-1))] 

但我接收錯誤

錯誤==> octavesubband在40 W13 = [零（大小（ 1：N-1））V3（1：長度（V3） - （N-1））]; ％插入延遲z ^（ - （N-））

我不知道修復它。請幫幫我。由於

Answer 1

以及它開始通過看你正試圖將數組的大小：

>> size(v3(1:length(v3)-(N-1))) 

ans = 

     2483   1 

>> size(zeros(size(1:N-1))) 

ans = 

    1 17 

這表明你需要轉其中的一個：

w13= [zeros(size(1:N-1))'; v3(1:length(v3)-(N-1))]; 

或

w13= [zeros(size(1:N-1)) v3(1:length(v3)-(N-1))'];