升級1.3後 - > 2.4：找到（）不參加相關車型

Question

我最近升級我的1.3應用2.4 https://github.com/dereuromark/upgrade
但現在的$這個 - >型號 - >找到一些用法（）沒有按沒有工作。特別是與相關模型/表格的連接。
產生「where列中的未知列'Bill.customer_id'」。

我的設置：

表和協會：http://i.stack.imgur.com/bjOIz.png（圖）

模式：

App::uses('AppModel', 'Model'); 
class Customer extends AppModel { 
public $actsAs = array('Logable', 'Containable'); 
public $hasMany = array(
    'Bill' => array(
     'className' => 'Bill', 
     'foreignKey' => 'customer_id', 
     'dependent' => false, 
     'conditions' => '', 
     'fields' => '', 
     'order' => '', 
     'limit' => '', 
     'offset' => '', 
     'exclusive' => '', 
     'finderQuery' => '', 
     'counterQuery' => '' 
    )... 
----------------------------------------------------------------- 
App::uses('AppModel', 'Model'); 
class Bill extends AppModel { 
public $actsAs = array('Containable', 'Logable', 'Lockable'); 

public $belongsTo = array(
    'Customer' => array(
     'className' => 'Customer', 
     'foreignKey' => 'customer_id', 
     'conditions' => '', 
     'fields' => '', 
     'order' => '' 
    )... 

public $hasAndBelongsToMany = array(
    'Stage' => array(
     'className' => 'Stage', 
     'joinTable' => 'bills_stages', 
     'foreignKey' => 'bill_id', 
     'associationForeignKey' => 'stage_id', 
     'unique' => true, 
     'conditions' => '', 
     'fields' => '', 
     'order' => '', 
     'limit' => '', 
     'offset' => '', 
     'finderQuery' => '', 
     'deleteQuery' => '', 
     'insertQuery' => '' 
    )... 
-------------------------------------------------------------- 
App::uses('AppModel', 'Model'); 
class BillsStage extends AppModel { 
public $actsAs = array('Containable', 'Logable', 'Lockable'); 

public $belongsTo = array(
    'Bill' => array(
     'className' => 'Bill', 
     'foreignKey' => 'bill_id', 
     'conditions' => '', 
     'fields' => '', 
     'order' => '' 
    ), 
    'Stage' => array(
     'className' => 'Stage', 
     'foreignKey' => 'stage_id', 
     'conditions' => '', 
     'fields' => '', 
     'order' => '' 
)... 
-------------------------------------------------------- 
App::uses('AppModel', 'Model'); 
class Stage extends AppModel { 
public $displayField = 'name'; 
public $actsAs = array('Tree', 'Containable', 'Logable'); 

public $hasMany = array(
    'Bill' => array(
     'className' => 'Bill', 
     'foreignKey' => 'stage_id', 
     'dependent' => false, 
     'conditions' => '', 
     'fields' => '', 
     'order' => '', 
     'limit' => '', 
     'offset' => '', 
     'exclusive' => '', 
     'finderQuery' => '', 
     'counterQuery' => '' 
    )... 

public $hasAndBelongsToMany = array(
    'Bill' => array(
     'className' => 'Bill', 
     'joinTable' => 'bills_stages', 
     'foreignKey' => 'stage_id', 
     'associationForeignKey' => 'bill_id', 
     'unique' => true, 
     'conditions' => '', 
     'fields' => '', 
     'order' => '', 
     'limit' => '', 
     'offset' => '', 
     'finderQuery' => '', 
     'deleteQuery' => '', 
     'insertQuery' => '' 
    )... 

在1.3的連接被工作。在2.4中只有一維sql查詢。

有什麼想法？

- 編輯 -

$billsStages = $this->Customer->Bill->BillsStage->find('all', array(
    'conditions' => array(
     'Bill.customer_id' => $this->Customer->id, 
     'Stage.id' => array_keys($vk_stages) 
    ), 
    'order' => 'BillsStage.created DESC' 
)); 

Answer 1

嘗試聯接

$options['joins'] = array(
    array('table' => 'bills', 
     'alias' => 'Bill', 
     'type' => 'LEFT', 
     'conditions' => array(
      'Bill.customer_id' => $this->Customer->id, 
     ) 
    ), 
    array('table' => 'stages', 
     'alias' => 'Stage', 
     'type' => 'LEFT', 
     'conditions' => array(
      'Stage.id' => array_keys($vk_stages) 
     ) 
    ) 
); 

$options['conditions'] = array(); 

$items= $this->Customer->Bill->BillsStage->find('all', $options); 

（從docs取出例子）（調整到你的情況）。

根據this answer，對於輔助模型上的條件，contain是不可能的，因爲contain進行了不同的查詢。因此，如果您希望在二級模型上應用條件，請使用連接，或者在您的模型中創建一個簡單函數，該函數執行兩個單獨的查詢，並創建一個宏數組，以便在使用contain時返回混合結果。