作出查詢一樣多variables.please幫我做一個查詢短

Question

這就是我的SQL查詢

$stmt = $con->prepare("select * from fistevent WHERE row_name LIKE 'A%' And Event_Id =? OR row_name LIKE 'B%' And Event_Id =? OR row_name LIKE 'C%' And Event_Id =? OR row_name LIKE 'D%' And Event_Id =? OR row_name LIKE 'E%' And Event_Id =? order by row_name ASC"); 
$stmt->bind_param("s", $_POST['EventId']); 
     $stmt->execute(); 
     $result = $stmt->get_result(); 

如何從價值與陣列數據庫比較來自HTML在我的代碼

$TicketType =$_POST['Tickettype']; 
$seatS=$_POST['finalSeats']; 
$EventId=$_POST["Eventid"]; 
$sqlData = array(); 

從數據庫中獲取結果

$stmt = $con->prepare("SELECT * FROM fist WHERE `Id`=? AND `Type`=?") or die($con->error); 

結合的結果

$stmt->bind_param("ss",$EventId , $TicketType); 
$stmt->execute(); 
$stmt->store_result(); 
$stmt-> bind_result($id,$Event_Id,$TicketType,$seats); 
if($stmt->fetch()) 
{ 
$data[] = array($id,$Event_Id,$TicketType,$seats); 
$Tickettype=$TicketType; 
$Rowname=$row_name; 
$Seats=$seats; 
$cats = array_filter(array_map('trim', explode(',', $seatS))); 
foreach($cats as $key => $cat) { 

在這裏，我想比較$貓與數據庫值$席位，但

while($Seats==$cat) 
{ 
echo "already hold"; 
} 
else 
{ 
echo "hold the seats"; 
} 
} 
} 

Answer 1

好像你有相同的事項標識，所以你可以使用查詢如

select * from fistevent WHERE (row_name LIKE 'A%' OR row_name LIKE 'B%' OR row_name LIKE 'C%' OR row_name LIKE 'D%' OR row_name LIKE 'E%') And Event_Id =? order by row_name ASC