PHP echo html table error

我已經使用數據庫中的數據創建了一個表來創建它我使用循環從我需要的列中獲取每一條數據。現在，我在輸入的HTMLonClick中調用了javascript函數。但是，我不斷收到錯誤。該功能似乎工作，這只是實際的echo，似乎是給出了錯誤。它在第58行，你可以看到我正在創建一個表並插入行。PHP echo html table error

UPDATE

我的JavaScript功能正在工作。錯誤是當它試圖設置<td>寬度和對齊。我得到的錯誤是：

未捕獲的SyntaxError：無效的或意外的標記

<?php 
    ob_start(); 
    session_start(); 
    require_once 'dbconnect.php'; 
    if(!isset($_SESSION['user'])) { 
     header("Location: index.php"); 
     exit; 
    } 
    $deny = array("222.222.222", "333.333.333"); 
    if (in_array ($_SERVER['REMOTE_ADDR'], $deny)) { 
     header("location: http://www.google.com/"); 
     exit(); 
    } 
    $res=mysqli_query($con,"SELECT * FROM users WHERE userId=".$_SESSION['user']); 
    $userRow=mysqli_fetch_array($res); 
?> 
<!DOCTYPE html> 
<html> 
    <?php header("Access-Control-Allow-Origin: http://www.py69.esy.es"); ?> 
    <head> 
     <title>ServiceCoin</title> 
     <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
     <link rel="stylesheet" href="assets/css/bootstrap.min.css" type="text/css" /> 
     <link rel="stylesheet" href="scripts/home/index.css" /> 
    </head> 
    <body> 
     <ul> 
      <li><a href="#" class="a">ServiceCoin.com(image)</a></li> 
      <li><a href="logout.php?logout" class="a">Sign Out</a></li> 
      <li><a href="#" class="a">Contact</a></li> 
      <li><a href="#" class="a">Get Service Coins</a></li> 
      <li><a href="#" class="a">News</a></li> 
      <li><a href="settings.php" class="a">Settings</a></li> 
      <li><a href="#" class="a">Referrals</a></li> 
      <li><a href="service.php" class="a">Services</a></li> 
      <li><a href="home.php" class="a">Home</a></li> 
     </ul> 
     <br /><br /> 
     <center> 
     <h3>Welcome, <?php echo $userRow['userName']; ?>. You Currently Have <span id="services"><?php echo $userRow['userServices']; ?></span> Services</h3> 
     <p id="error"></p> 
     <button onclick="send_coins()" class="button">Send Coins</button> 
     <button onclick="create_service()" class="button">Create A Service</button> 
     <button onclick="send_coins()" class="button">My Services</button> 
     <h3>View Services</h3> 
     <span><?php 
     $users = 1; 
     $num = 1; 
     echo "<center><table width=1000><th>Buy</th><th>Service Name</th><th>Service Cost</th><th>Service Description</th><th>Service Provider Name</th>"; 
     while($users < 100 && $num < 100){ 
      $res=mysqli_query($con,"SELECT * FROM users WHERE userId=".$users); 
      $userRow=mysqli_fetch_array($res); 
      $id = 0; 
      while($id != 10){ 
       $id = $id + 1; 
       if($userRow['userService'.$id] === 'null'){ 
       }else if(!empty($userRow['userService'.$id])){ 
       echo "<tr class=services ><td name=".$num."><input type=submit onClick='buy(".$userRow['userService'.$id].",".$userRow['userServiceCost'.$id].",".$userRow['userServiceEmail'].")'></td><td width='250' align='center'>".$userRow['userService'.$id]."</td><td width='250' align='center'>".$userRow['userServiceCost'.$id]."</td><td width='250' align='center'>".$userRow['userServiceDes'.$id]."</td><td width='250' align='center'>".$userRow['userServiceName'.$id]."</td></tr>"; 

       //echo $id."Error: ".$con->error;   
       $num = $num + 1; 
       } 
      } 
      $users = $users + 1; 
     } 
     echo "All Services Loaded"; 
     echo "</table></center>"; 
     ?></span> 
      <span class="text-danger"><?php echo $msg; ?></span> 
     </center> 
    </body> 
    <script lang="text/javascript" src="scripts/home/index.js"></script>  
    <script type="text/javascript"> 


function buy(sid, scost, semail){ 
    console.log(sid,scost,semail); 
} 

</script> 
</html> 
<?php ob_end_flush(); ?>

來源

2016-11-17 Morgan Clarke

的可能的複製[如何從PHP調用JavaScript函數？（http://stackoverflow.com/questions/1045845/how-to-call-a-javascript-function-from-php ） –

看看編輯請 –

''td width ='250'align ='center'>「'把單引號放在所示位置，看看有沒有幫助 – Blinkydamo

正如我在上面提到的意見，你需要使用引號的所有屬性和JS調用。此外，請注意您的onClick的內容必須是有效的JS。因此，作爲參數傳遞給函數的字符串應該用引號引起來。

echo '<tr class="services"><td name="'.$num.'"><input type="submit" onClick="buy(\''.$userRow['userService'.$id].'\',\''.$userRow['userServiceCost'.$id].'\',\''.$userRow['userServiceEmail'].'\')"></td><td width="250" align="center">'.$userRow['userService'.$id].'</td><td width="250" align="center">'.$userRow['userServiceCost'.$id].'</td><td width="250" align="center">'.$userRow['userServiceDes'.$id].'</td><td width="250" align="center">'.$userRow['userServiceName'.$id].'</td></tr>';

來源

2016-11-17 20:04:22 Steve

是的，抱歉，我注意到了，忘記了更新這裏的代碼。對不起，這並沒有解決它 –

PHP echo html table error

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