範圍內的數字（）代碼沒有返回預期的結果

Question

我正在學習Python，現在正在使用簡單的代碼編寫和if-elif-else語句。 我有這樣的代碼塊，總是返回else語句，即使我把數字1和30

elif door == "3": 
     print "This is a winning treasure room, congratulations!" 
     print "Pick a number between 1 and 30" 

     number = raw_input ("> ") 

     if number in range (1,10): 
      print "that's a number between 1 and 10" 

     elif number in range (11, 20): 
      print "that's a number between 11 and 20" 

     elif number in range (21, 30): 
      print "that's a number between 21 and 30" 

     else: 
      print "that's not a number we asked for" 

之間我也然後設法：

elif door == "3": 
     print "This is a winning treasure room, congratulations!" 
     print "Pick a number between 1 and 30" 

     number = raw_input ("> ") 

     if number == number in range (1,10): 
      print "that's a number between 1 and 10" 

     elif number == number in range (11, 20): 
      print "that's a number between 11 and 20" 

     elif number == number in range (21, 30): 
      print "that's a number between 21 and 30" 

     else: 
      print "that's not a number we asked for" 

我也嘗試：

if number == x in range (1, 10): 

但是，當然x沒有定義，它會出現一個錯誤。

任何指導讚賞。

Answer 1

raw_input()將輸入轉換爲字符串。您需要將其轉換爲整數。

number = int(raw_input ("> ")) 

的raw_input（）：

然後該功能可以讀取從輸入的線，將其轉換成字符串 （剝離的後換行），並返回。

從doc