我想知道如何知道端口音頻測試例子的關係以及如何獲取頻率。我想知道如何發送特定頻率到聲卡? 1.如何知道代碼發送到聲卡的具體頻率 2.我怎樣才能發送sin(2 * pi * f * t)和sin((2 * pi * f * t)-3.14)是一個延遲版本。這是代碼。任何幫助高度讚賞如何知道端口音頻採樣測試正弦波代碼的頻率
#include <stdio.h>
#include <math.h>
#include "portaudio.h"
#define NUM_SECONDS (20)
#define SAMPLE_RATE (44100)
#define AMPLITUDE (0.9)
#define FRAMES_PER_BUFFER (64)
#define OUTPUT_DEVICE Pa_GetDefaultOutputDeviceID()
//#define OUTPUT_DEVICE (2)
#ifndef M_PI
#define M_PI (3.14159265)
#endif
#define TABLE_SIZE (200)
typedef struct
{
float sine[TABLE_SIZE];
int left_phase;
int right_phase;
}
paTestData;
static int patestCallback( void *inputBuffer, void *outputBuffer,
unsigned long framesPerBuffer,
PaTimestamp outTime, void *userData)
{
paTestData *data = (paTestData*)userData;
float *out = (float*)outputBuffer;
unsigned long i;
int finished = 0;
(void) outTime; /* Prevent unused variable warnings. */
(void) inputBuffer;
for(i=0; i<framesPerBuffer; i++)
{
*out++ = data->sine[data->left_phase]; /* left */
*out++ = data->sine[data->right_phase]; /* right */
data->left_phase += 1;
if(data->left_phase >= TABLE_SIZE) data->left_phase -= TABLE_SIZE;
data->right_phase +=2.57; /* higher pitch so we can distinguish left and right. */
if(data->right_phase >= TABLE_SIZE) data->right_phase -= TABLE_SIZE;
}
return finished;
}
/*******************************************************************/
int main(void);
int main(void)
{
PortAudioStream *stream;
PaError err;
paTestData data;
int i;
printf("PortAudio Test: output sine wave. SR = %d, BufSize = %d, devID = %d\n",
SAMPLE_RATE, FRAMES_PER_BUFFER, OUTPUT_DEVICE);
/* initialise sinusoidal wavetable */
for(i=0; i<TABLE_SIZE; i++)
{
data.sine[i] = (float) (AMPLITUDE * sin(((double)i/(double)TABLE_SIZE) * M_PI * 2.));
}
data.left_phase = data.right_phase = 0;
err = Pa_Initialize();
if(err != paNoError) goto error;
err = Pa_OpenStream(
&stream,
paNoDevice,/* default input device */
0, /* no input */
paFloat32, /* 32 bit floating point input */
NULL,
OUTPUT_DEVICE,
2, /* stereo output */
paFloat32, /* 32 bit floating point output */
NULL,
SAMPLE_RATE,
FRAMES_PER_BUFFER,
0, /* number of buffers, if zero then use default minimum */
paClipOff, /* we won't output out of range samples so don't bother clipping them */
patestCallback,
&data);
if(err != paNoError) goto error;
err = Pa_StartStream(stream);
if(err != paNoError) goto error;
printf("Play for %d seconds.\n", NUM_SECONDS); fflush(stdout);
Pa_Sleep(NUM_SECONDS * 1000);
err = Pa_StopStream(stream);
if(err != paNoError) goto error;
err = Pa_CloseStream(stream);
if(err != paNoError) goto error;
Pa_Terminate();
printf("Test finished.\n");
return err;
錯誤: Pa_Terminate(); fprintf(stderr,「使用portaudio流時發生錯誤\ n」); fprintf(stderr,「錯誤號碼:%d \ n」,err); (stderr,「錯誤消息:%s \ n」,Pa_GetErrorText(err)); return err; }
謝謝!我打破了我的想法,試圖理解採樣率,表格大小和相位增量之間的關係,現在一切都清楚了! =) – rcorreia