您總是可以將您的密碼發佈到neo4j transactional end point。
如果你發佈這樣的事情...
{
"statements": [
{
"statement": "match (a:Moo {name: 'A'}) RETURN {id: id(a)} as id, {list : [{colour: a.colour}, {colour: a.other_colour}]} as list"
}
]
}
你還是會回到這樣的事情...
{
"results": [
{
"columns": [
"id",
"list"
],
"data": [
{
"row": [
{"id" : 2723},
{"list" :
[
{"colour" : "black"},
{"colour" : "blue"}
]
}
]
},
{
"row": [
{"id" : 2724},
{"list" :
[
{"colour" : "green"},
{"colour" : "purple"}
]
}
]
}
]
}
],
"errors": [ ]
}
或者,如果你想要的屬性值,你可以做這樣的事情結合在同一個對象中,您可以發佈此密碼並獲取返回
{
"statements": [
{
"statement": "match (a:Moo {name: 'A'}) RETURN {id: id(a), list: [ {colour: a.colour},{colour: a.other_colour}]} as data"
}
]
}
並且有東西li柯本返回
{
"results": [
{
"columns": [
"data"
],
"data": [
{
"row": [
{"id" : 2723,
"list" :
[
{"colour" : "black"},
{"colour" : "blue"}
]
}
]
},
{
"row": [
{"id" : 2724,
"list" :
[
{"colour" : "green"},
{"colour" : "purple"}
]
}
]
}
]
}
],
"errors": [ ]
}
不是真的我想用它,因爲我更新了較大有限嵌套對象 – Nayish 2015-03-02 21:57:21
什麼即時尋找,因爲我想嵌套的對象,以及...的例子只有兩個級別的對象,但查詢和響應以包括數據中的屬性名稱。更緊密? – 2015-03-02 22:14:41
有限。沒有無限......如果我在這裏使用它,我的示例如何選擇看起來如何?它是否只是一個行的每個對象...因爲這就是我要找的東西? – Nayish 2015-03-02 22:16:11