如何textview和安卓

Question

我想創建一個對話框，包含我的網站的鏈接（在Android），並希望手機的瀏覽器打開時，用戶點擊鏈接。我目前有：

@Override 
protected Dialog onCreateDialog (int id){ 
Dialog dialog = new Dialog(MyActivity.this);             

dialog.setContentView(R.layout.custom_dialog); 
dialog.setTitle("MyTittle"); 
ImageView image = (ImageView)dialog.findViewById(R.id.image); 

image.setImageResource(R.drawable.launcher_icon); 
TextView lblClickable = (TextView)findViewById(R.id.text); 
String htmlText = "Link to my <a HREF='http://www.rainbowbreeze.it'>site</a>"; 
lblClickable.setText(Html.fromHtml(htmlText)); 
//needed to enable click on the link  
lblClickable.setMovementMethod(LinkMovementMethod.getInstance()); 
return dialog; } 

上面的代碼觸發NullPointerException異常中包含lblClickable.setText(Html.fromHtml(htmlText));任何建議行？代碼有什麼問題？

Answer 1

我覺得lblClickable爲空，這條線大概是錯誤的：

TextView lblClickable = (TextView)findViewById(R.id.text); 

更正：

TextView lblClickable = (TextView)dialog.findViewById(R.id.text);