我試圖使$name
,$email
和$message
在一個腳本中驗證,而不會使它們看起來像一個錯誤(使它們都是紅色),而不是實際上不正確的。PHP多重驗證
她是我使用的代碼:
PHP:
<?php
$name = $_POST['name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$visitors_site = $_POST['site'];
$message = $_POST['message'];
$email_from = '[email protected]';
$email_subject = 'New Contact Submission';
$to = '[email protected]';
$headers = "From:" . $email;
$headers = "Contact Submission From: " . $email;
$message1 = "Name: " . $name;
$message2 = "\n\nEmail: " . $email;
$message3 = "\n\nPhone: " . $phone;
$message4 = "\n\nTheir Site: " . $visitors_site;
$message5 = "\n\nMessage: " . $message;
$email_body = $message1 . $message2 . $message3 . $message4 . $message5;
if (!filter_var($email, FILTER_VALIDATE_EMAIL) === false) {
mail($to, $email_subject, $email_body,$headers);
exit(json_encode(array('error' => 0)));
} else {
exit(json_encode(array('error' => 1)));
}
if ($name == "") {
exit(json_encode(array('error' => 1)));
} else {
mail($to, $email_subject, $email_body,$headers);
exit(json_encode(array('error' => 0)));
}
?>
AJAX腳本:
var sendEmail = function(){
var url = 'main.php';
$.ajax({
url : url,
type : "POST",
dataType : "JSON",
data : $('#contact-form').serialize(),
success : function(response) {
if (response.error == 0) {
$('#contact-form')[0].reset();
alert('Form submitted successfully. We will contact you asap.');
} else {
$('#email-input').css('color', 'red');
alert('ERROR MESSAGE');
}
}
})
return false;
}
HTML:
<div id="contact">
<div class="container">
<form id="contact-form" method="post" onsubmit="return sendEmail()">
<h1>Contact Form</h1>
<fieldset>
<input placeholder="Your Name" type="text" name="name" id="name-input" required value="<?php echo isset($_POST['name']) ? $_POST['name'] : ''; ?>">
</fieldset>
<fieldset>
<input placeholder="Your Email Address" type="email" name="email" id="email-input" required value="<?php echo isset($_POST['email']) ? $_POST['email'] : ''; ?>">
</fieldset>
<fieldset>
<input placeholder="Your Phone Number (optional)" type="tel" name="phone" required>
</fieldset>
<fieldset>
<input placeholder="Your Web Site (optional)" type="url" name="site" required>
</fieldset>
<fieldset>
<textarea placeholder="Type your message here...." name="message" required value="<?php echo isset($_POST['email']) ? $_POST['email'] : ''; ?>"></textarea>
</fieldset>
<fieldset>
<button type="submit" id="contact-submit" name="submit">Submit</button>
</fieldset>
</form>
</div>
</div>
提交按鈕沒有做任何事情或代碼是錯誤的。當我按下提交按鈕時沒有任何事情發生 –
然後開始尋找標準的JS調試。錯誤控制檯等相當肯定沒有語法錯誤在我的代碼上面介紹。 – miken32
我看到有兩個人,在信息和名字錯誤後錯過了';'。 –