在mysql數據庫中使用tinyint列的Hibernate句柄？

Question

在我的Hibernate應用程序中有一個字段Active它是布爾類型。 我休眠Bean類列

@Column(name = "ACTIVE") 
@Type(type = "org.hibernate.type.YesNoType") 
private boolean active; 
//Setter and getter methods 

在我的服務類writig代碼...

public void createUser(UserVO userVO) throws Exception { 
    -------- 
    userVO.setActive(false);//setting false.. 
    ---- 
    ------//Database insert Code hear.. 
} 

但我發現了異常聽到..

Caused by: java.sql.BatchUpdateException: Incorrect integer value: 'N' for column 'ACTIVE' at row 1 
    at com.mysql.jdbc.PreparedStatement.executeBatchSerially(PreparedStatement.java:2045) 
    at com.mysql.jdbc.PreparedStatement.executeBatch(PreparedStatement.java:1468) 
    at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:70) 
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:268) 
    ... 50 more 
Caused by: java.sql.SQLException: Incorrect integer value: 'N' for column 'ACTIVE' at row 1 
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1073) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4096) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4028) 
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2490) 
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2651) 
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2683) 
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2144) 
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2444) 
    at com.mysql.jdbc.PreparedStatement.executeBatchSerially(PreparedStatement.java:1997) 
    ... 53 more 

Answer 1

您的問題這裏有兩種解決方案，

1，如果該類型ACTIVE列{} TINYINT，你應該在你的代碼 如使用短號碼。

userVO.setActive(Short.valueOf("0")); 

2，如果你在你的代碼中使用布爾類型，請change the type of ACTIVE column to {char}

祝你好運！

Answer 2

從hibernate types docs：

org。 hibernate.type.YesNoType

將布爾值映射爲JDBC CHAR類型as（'N'| 'N'）= FALSE，（ 'Y' | 'Y' ）=真

所以表列類型（TINYINT）不適合握住你的價值。使其成爲char或varchar。