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我想添加JSON對象作爲字符串到我的數據庫。我使用下面的代碼:Android的SQLite數據類型不匹配
public static final String SQL_CREATE_TABLE =
"CREATE TABLE " + TABLE_NAME + "("
+ KEY_PRIMARY + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ COLUMN_ID + " TEXT, "
+ COLUMN_TITLE + " TEXT, "
+ COLUMN_AUTHOR + " TEXT, "
+ COLUMN_VOTES + " TEXT, "
+ COLUMN_SEARCH + " TEXT)";
public int insertQuestion3(Context c,String ids,String titles,String authors,String votes,String search)
{
DatabaseWrapper databaseWrapper = new DatabaseWrapper(c);
Log.e("ERROR2", String.valueOf(isDatabaseOpened()));
myDataBase = databaseWrapper.getWritableDatabase();
long questionId = 0;
if (isDatabaseOpened()) {
ContentValues values = new ContentValues();
values.put(QuestionORM.COLUMN_ID, ids);
values.put(QuestionORM.COLUMN_TITLE,titles);
values.put(QuestionORM.COLUMN_AUTHOR, authors);
values.put(QuestionORM.COLUMN_VOTES, votes);
values.put(QuestionORM.COLUMN_SEARCH, search);
questionId = myDataBase.insert(QuestionORM.TABLE_NAME, "null", values);
Log.e(TAG, "Inserted new Question with ID: " + questionId);
myDataBase.close();
}
return (int) questionId;
}
而且在活動:
holdid = new JSONObject();
holdid.put("uniqueIDs", new JSONArray(ids));
String _id = holdid.toString();
Log.e("VALUE5",_id);
holdauthor = new JSONObject();
holdauthor.put("uniqueAuthors",new JSONArray(authors));
String _auth = holdauthor.toString();
Log.e("VALUE4",_auth);
holdtitle = new JSONObject();
holdtitle.put("uniqueTitles",new JSONArray(titles));
String _title = holdtitle.toString();
Log.e("VALUE2",_title);
holdvotes = new JSONObject();
holdvotes.put("uniqueVotes",new JSONArray(votes));
String _vote = holdvotes.toString();
Log.e("VALUE",_vote); q.insertQuestion3(MainActivity.this,_id,_title,_auth,_vote,val);
但我得到的邏輯以下錯誤:
放棄語句以5:INSERT INTO問題(?,?,?,?,?,?)]數據類型不匹配
但是它們都具有相同的數據類型,即TEXT。
我收到這條線上此錯誤:
questionId = myDataBase.insert(QuestionORM.TABLE_NAME, "null", values);
但他們都具有相同的數據類型,即TEXT和同樣,questionId返回爲-1。
我該如何解決這個問題?
謝謝!
您是否在嘗試插入之前更改了表創建SQL SQL_CREATE_TABLE? – inmyth