Hibernate查詢多個對象選擇

Question

我有這樣一個實體模型：

public class Facture implements Serializable 
{ 
@Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_FACTURE") 
private long idFacture; 
... 

private Panier panier; 
    ... 
} 

public class Panier 
{ 
@Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_PANIER") 
private long idPanier; 

@ManyToOne 
private Client client; 
@OneToMany 
private List<LignePanier> articles = new ArrayList<LignePanier>(); 
... 
} 

public class Client 
{ 
@Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SEQ_CLIENT") 
private long idClient; 
... 
    } 

所以我想從一個客戶端X. 查詢所有骨折我嘗試這樣：

public List<Facture> listeFacture(Long clientID) { 
    List<ParameterMap> parameters = new ArrayList<ParameterMap>(); 
    parameters.add(new ParameterMap(StandardBasicTypes.LONG, clientID)); 
    return dao.query("select facture from Facture facture where facture.panier.client.idClient = ?", parameters); 
} 

我得到這個異常：

org.hibernate.QueryException: could not resolve property: client of: be.infoserv.web.model.Facture [select facture from be.infoserv.web.model.Facture facture where facture.panier.client.idClient = ?] 

我認爲這是不可能的查詢穿透式對象像這個，但我不知道如何寫這個查詢...

對不起，我是一個法國用戶。

Answer 1

您可能需要使用內部連接要做到這一點：

select facture 
from Facture facture 
    inner join facture.panier as panier 
    inner join panier.client as client 
where client.clientId = ? 

或者使用標準它可以是一個比較安全，因爲你不能弄髒的HQL：

Criteria factureCrit = session.createCriteria(Facture.class); 
Criteria panierCrit = factureCrit.createCriteria("panier"); 
Criteria clientCrit = panierCrit.createCriteria("client"); 
clientCrit.add(Restrictions.idEq(clientId)); 

return factureCrit.list();