初始化陣列的與硬編碼和生成的值

Question

此代碼，其初始化與兩個硬編碼值的陣列的組合工作完全正常：

var db = new GoogleGraph { 
    cols = new ColInfo[] { 
     new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
     new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" }      
    }.ToList(), 
    rows = new List<DataPointSet>() 
}; 
db.cols.AddRange(listOfValues.Select(p => new ColInfo { id = "", label = p, type = "number" })); 

此代碼，它試圖增加一些動態生成的值不工作：

var db = new GoogleGraph { 
    cols = new ColInfo[] { 
     new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
     new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" }, 
     listOfValues.Select(p => new ColInfo { id = "", label = p, type = "number" })      
    }.ToList(), 
    rows = new List<DataPointSet>() 
}; 

我該如何正確實現上面的代碼片段？

Answer 1

您不能將IEnumerable<T>傳遞給T[]這樣的初始化程序。

你可以做你想做的通過將在自己的收藏硬編碼的對象，然後連接動態的：

var db = new GoogleGraph { 
    cols = 
     new ColInfo[] { 
      new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
      new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" } 
     } 
     .Concat(listOfValues.Select(p => 
      new ColInfo { id = "", label = p, type = "number" }))      
     .ToList(), 
    rows = new List<DataPointSet>() 
};