傳遞給每個（）的變量不是數組或對象

Question

我真的不明白爲什麼我得到這個錯誤或如何解決它！ 變量傳遞給每個（）不是上啉

while(list($key,$value) = each($_FILES['images']['name'])) 

完整代碼 -

$max_no_img=4; // Maximum number of images value to be set here 
$imgs_names = array('CV', 'Research Plan', 'Degree Transcript', 'GRE Scores'); 

echo "<form method=post action='' enctype='multipart/form-data'>"; 
echo "<table border='0' width='400' cellspacing='0' cellpadding='0' align=left>"; 
for($i=1; $i<=$max_no_img; $i++){ 
echo "<tr><td>".$imgs_names[$i-1]."</br</td><td> 
<input type=file name='images[]' class='bginput'></td></tr>"; 
} 

echo "<tr><td colspan=2 align=center><input type=submit value='Submit'></td></tr>"; 
echo "</form> </table>"; 

while(list($key,$value) = each($_FILES['images']['name'])) 
{ 

echo $key; 
echo "<br>"; 
echo $value; 
echo "<br>"; 
if(!empty($value)){ // this will check if any blank field is entered 
$filename =rand(1,100000).$value; // filename stores the value 

$filename=str_replace(" ","_",$filename); 

$add = "upload/$filename"; // upload directory path is set 

copy($_FILES['images']['tmp_name'][$key], $add); 
echo $add; 

任何想法數組或對象？

Answer 1

$_FILES['images']['name]不是數組，$_FILES['images']是。

所以

while (list($key, $object) = each($_FILES['images'])) 
{ 
    //use $object['name'] or $object['tmp_name'] 
} 

Answer 2

$_FILES['images']['name']不是一個數組！它是數組內的一個值。

如果要遍歷文件，你應該：

while(list($key,$value) = each($_FILES['images']) { 
(...) 
}