2015-04-28 56 views
-1

我需要一個查詢,它將賦予與某些值相對應的行是強制性的,無論其值是否爲空值或這些值在表中都不存在。MySQL:查詢獲得一些強制行

E.g.

SELECT spot_key, market,panel_member, SUM(weight) as TVR 
FROM break_minute_tvr_fixed b 
WHERE b.column1 in (1,3,4,2,3,4) 
    and b.section in (1,2,3,4) 
    and b.sex in (1,2) 
    and b.age in (1,2,3,4,5,6,7) 
    and b.market in ('9') 
    and spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

這將返回行爲:

+-----------------+--------+---------------------+--------------------+ 
| spot_key  | market | panel_member  | TVR    | 
+-----------------+--------+---------------------+--------------------+ 
| 1:20141017:2129 | 9  | 010583010102;7.2930 | 134.65280079841614 | 
+-----------------+--------+---------------------+--------------------+ 
1 row in set (0.00 sec) 

現在,如果我添加其他價值的市場名單好比說300不那麼本身我的查詢變得表存在:

SELECT spot_key, market,panel_member, SUM(weight) as TVR 
    FROM break_minute_tvr_fixed b 
WHERE b.column1 in (1,3,4,2,3,4) 
    and b.section in (1,2,3,4) 
    and b.sex in (1,2) 
    and b.age in (1,2,3,4,5,6,7) 
    and b.market in ('9','300') 
    and spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

它給了我與上面相同的輸出。但我需要的東西象下面這樣:

+-----------------+--------+---------------------+--------------------+ 
| spot_key  | market | panel_member  | TVR    | 
+-----------------+--------+---------------------+--------------------+ 
| 1:20141017:2129 | 300 |      | 0     | 
| 1:20141017:2129 | 9  | 010583010102;7.2930 | 134.65280079841614 | 
+-----------------+--------+---------------------+--------------------+ 
+0

刪除「GROUP BY」子句後你嘗試過嗎? –

+0

因此在'break_minute_tvr_fixed'中沒有'market' ='300'的行,但是您想要在結果中顯示它們以及'spot_key'嗎?旁邊的問題:你爲什麼只用1個'spot_key'?你能有超過1個spot_key嗎?如果是的話,希望的輸出是什麼?所有的「spot_key」和「market」配對? – Doon

+0

是@Doon你是對的。在「in」子句中我們可以有多個spot_key。 在這種情況下,我需要所有的組合。 –

回答

2

您可以用left join做到這一點:

SELECT spot_key, m.market, panel_member, SUM(weight) as TVR 
FROM (SELECT '9' as market UNION ALL SELECT '300' 
    ) LEFT JOIN 
    break_minute_tvr_fixed b 
    ON b.market = m.market and 
     b.column1 in (1,3,4,2,3,4) and 
     b.section in (1,2,3,4) and 
     b.sex in (1,2) and 
     b.age in (1,2,3,4,5,6,7) and 
     b.spot_key in ('1:20141017:2129') 
GROUP BY spot_key, market; 

當然spot_key中會NULL,除非你明確地給它分配一個值:

SELECT '1:20141017:2129' as spot_key, m.market, panel_member, SUM(weight) as TVR