您可以使用此方法,這將工作適合你 只是傳遞圖像的路徑(在您的形象是你的ImageView存儲和對象引用的第二個參數)
1st argument Path of images want ot display
2nd argument object reference of `ImageView`
public static void ShowPicture(String filePath, ImageView pic) {
File f = new File(filePath);
FileInputStream is = null;
try {
is = new FileInputStream(f);
} catch (FileNotFoundException e) {
Log.d("error: ",String.format("ShowPicture.java file[%s]Not Found",fileName));
return;
}
Bitmap = BitmapFactory.decodeStream(is, null, null);
pic.setImageBitmap(bm);
}
也請放清單文件中的此權限
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />
logcat please? – 2015-03-19 10:22:49
跳出異常...什麼是異常? – Fahim 2015-03-19 10:22:56
路徑中的**空間**是否爲錯字? – 2015-03-19 10:24:06