我試圖構建完美的亞馬遜鏈接正則表達式在JavaScript中使用。這是我到目前爲止有:完美的亞馬遜鏈接正則表達式
var reg = /https?:\/\/(www|smile)\.amazon\.com\/(?:(?:[\w-]+\/)?(?:dp|gp\/product)\/(\w{10})\/)?/;
我想這符合所有完下列網址:
http://smile.amazon.com/dp/B0005ZH4QI/?tag=menasheh02-20&psc=1&smid=ATVPDKIKX0DER
http://www.amazon.com/gp/family/signup/info/?ie=UTF8&camp=1789&creative=9325&linkCode=ur2&ref_type=generic&refcust=5FNWKEJKP63HFBSY6JGLXL4XIQ&tag=menasheh02-20&linkId=HR76ZTGJKWO5ED2N
http://www.amazon.com/gp/redirect.html?ie=UTF8&location=https%3A%2F%2Fwww.amazon.com%2Fgp%2Fsubscribe-and-save%2Fmanager%2Fviewsubscriptions%3Fie%3DUTF8%26ref_%3Dya%255FT15%255F33&tag=menasheh02-20&linkCode=ur2&camp=1789&creative=390957
http://www.amazon.com/gp/student/signup/info?ie=UTF8&refcust=7EATHY4IXOFTTEMLIHVC3YL6DI&ref_type=generic
http://www.amazon.com/gp/video/primesignup?tag=menasheh02-20
https://smile.amazon.com/dp/B0005ZH4QI/?tag=menasheh02-20&psc=1&smid=ATVPDKIKX0DER
https://smile.amazon.com/s/ref=s9_acss_gb_cg_HTLLPCGB_3d1?fst=as%3Aoff&rh=n%3A165793011%2Cn%3A!2334111011%2Cn%3A!2334173011%2Cn%3A15539865011%2Cp_n_age_range%3A165936011%2Cp_72%3A1248963011&bbn=15539865011&ie=UTF8&qid=1476851901&rnid=1248961011&pf_rd_m=ATVPDKIKX0DER&pf_rd_s=events-center-c-4&pf_rd_r=8MKN8SY6C5ZP4NC1C0RB&pf_rd_t=701&pf_rd_p=e4acec8d-70de-466a-be44-05291b40a5d4&pf_rd_i=HTL_desktop
https://www.amazon.com/b/ref=s9_acss_gb_cg_HTLLPCGB_11a1?node=13521759011&pf_rd_m=ATVPDKIKX0DER&pf_rd_s=events-center-c-4&pf_rd_r=8MKN8SY6C5ZP4NC1C0RB&pf_rd_t=701&pf_rd_p=e4acec8d-70de-466a-be44-05291b40a5d4&pf_rd_i=HTL_desktop
https://www.amazon.com/Doctor-Vortex-Manipulator-Sonic-Screwdriver/dp/B001PR1ZII/ref=gbph_tit_e-7_fb02_fc8a0d34?smid=AOUT97QIB451U&pf_rd_p=8e268714-ad3d-444b-b0df-d51d8825fb02&pf_rd_s=events-center-c-7&pf_rd_t=701&pf_rd_i=HTL_desktop&pf_rd_m=ATVPDKIKX0DER&pf_rd_r=8MKN8SY6C5ZP4NC1C0RB
https://www.amazon.com/dp/B0005ZH4QI/?tag=menasheh02-20&psc=1&smid=ATVPDKIKX0DER
https://www.amazon.com/gp/coupon/skippy-baking-sale/A2UI00T2I5JAV3?ie=UTF8&heroAsin=B0005ZH4QI&source=grid_db_13285418011&pf_rd_p=782d30de-8b22-4b3d-9009-0f7a0cb995d3&pf_rd_s=merchandised-search-3&pf_rd_t=Landing&pf_rd_i=13285418011&pf_rd_m=ATVPDKIKX0DER&pf_rd_r=PPNJHXVZRMM4XP9KXGGG
https://www.amazon.com/Monster-High-School-Playset/dp/B006O6F932/ref=gbph_tit_e-7_fb02_85d3d028?smid=A3CXJV2JYTL237&pf_rd_p=8e268714-ad3d-444b-b0df-d51d8825fb02&pf_rd_s=events-center-c-7&pf_rd_t=701&pf_rd_i=HTL_desktop&pf_rd_m=ATVPDKIKX0DER&pf_rd_r=8MKN8SY6C5ZP4NC1C0RB
https://www.amazon.com/s/ref=s9_acss_gb_cg_HTLLPCGB_3d1?fst=as%3Aoff&rh=n%3A165793011%2Cn%3A!2334111011%2Cn%3A!2334173011%2Cn%3A15539865011%2Cp_n_age_range%3A165936011%2Cp_72%3A1248963011&bbn=15539865011&ie=UTF8&qid=1476851901&rnid=1248961011&pf_rd_m=ATVPDKIKX0DER&pf_rd_s=events-center-c-4&pf_rd_r=8MKN8SY6C5ZP4NC1C0RB&pf_rd_t=701&pf_rd_p=e4acec8d-70de-466a-be44-05291b40a5d4&pf_rd_i=HTL_desktop
而沒有這些:
https://www.google.com/search?safe=active&site=&source=hp&q=bad+regex&oq=bad+regex&gs_l=hp.3..0j0i22i30k1l9.724.2089.0.2265.10.9.0.0.0.0.269.1091.0j4j2.6.0....0...1c.1.64.hp..4.5.821.0..0i20k1j0i131k1j0i10k1.k62wRudUpsw
https://sellercentral.amazon.com/B53C945A8D?randomstuff=34341&otherrandomstuff=2
眼下,它不匹配任何一個壞的 - 這部分是相對簡單的。 (它也不匹配url中的gp/redirect.html?
)。棘手的部分是讓匹配分別返回url的每個有用部分,特別是考慮if/elses和#。
##工作
match[1]
應該等於或者 「WWW」 或 「笑臉」。
match[2]
應等於ASIN,或者是空白,如果該URL沒有/dp/%ASIN%
,%SEO-string%/dp/%ASIN%
,或/gp/product/%ASIN%
match[3]
應.COM之後等於URL的其餘部分,或者後產品如果設置了ASIN,但不包括#末尾
match[4]
應該等於從匹配開始[3]到tag=
(如果存在)。
match[5]
應等於標籤參數(如果存在)
match[6]
應等於標籤參數之間的網址的其餘部分(如果存在的話;否則空白)和#(如果它存在,否則到結束)
match[7]
應後,等於#末和任何東西,或空白,如果沒有一個
我剛剛進入更復雜的正則表達式,並卡住的東西好像不打算一路到該行的結尾,如果有#等等;.
任何人都可以更有經驗的幫助嗎?謝謝。
相反RegExp'構造的',使用正則表達式文字。 – Tushar
@Tushar用於匹配功能?你是什麼意思? – Menasheh
'var regex = /https?:\/\/(www|smile)\.amazon\.com\/((::([:[\w-]+\//??(?:dp|gp\/產品)\ /(\ W {10})\ /)([\ W \/= - ] +)([\ W \/= - ?]???+)(\ +)(#[\ w] +)?/;'然後_#不工作JS##問題將被解決。在'RegExp'構造函數中,字符串被傳遞時斜線需要被轉義。 – Tushar