SQL Server結合數據問題

嘿，我想把我的數據合併成一個總和。這是現在我的輸出：SQL Server結合數據問題

Amount 
--------- 
$258.0 
$400.0 
$1011.0 
$628.0 
$628.0 
$340.0 
$340.0 
$1764.0

當然總將是$ 5369。這是輸出的I型需要

Description | Quantity | Price | Amount 
-------------------------------------------- 
Fees   8   $1.50 $12.00 
Redep        $5369.00 

            $5381.00

只以上信息，我真的很需要的是，，5369.00和5381.00。

這是我的查詢來獲取我先貼這些值：

SELECT '$' + CONVERT(varchar(50),round((CONVERT(int,Points) * .1),0)) AS 'Amount' 
    FROM tblHGP HGP, 
     OrderDetails OD, 
     tblInvoices i 
    JOIN tblCS cs ON i.INumber = cs.INumber 
    JOIN tblECI ac ON i.INumber = ac.INumber 
WHERE cs.SoldTo = HGP.ECard 
    AND issued BETWEEN '2010-09-01' AND '2010-09-30 23:59:59' 
    AND Country = 'US' 
    AND HGP.iNumber = OD.orderdetail 
ORDER BY issued

來源

2010-10-22 StealthRT

在哪裏費，再沉積物，數量和價格都從何而來？你的表定義是什麼？ – 2010-10-22 15:58:42

它看起來好像Redep金額是所有金額數字的總和，數量是您的行數，費用金額是費用價格倍數和（未標記的）總金額是Redep金額+費用金額 - 但是，您沒有'沒有給出費用價格來自哪裏的任何跡象。你希望它被硬編碼爲1.50美元嗎？ – 2010-10-22 16:08:21

是的，費用是硬編碼在1.50不會改變。其數量X 1.50（8 x 1.50）即12。Redep Total是累計的金額。最後，Total是金額+ 12 = 5381.00的總和。 – StealthRT 2010-10-22 16:22:02

按照你澄清，如果你真的必須這樣做，所有在查詢本身，我認爲你需要這樣的東西。

DECLARE @Points float, @Qty int 

SELECT @Points = SUM(Points), @Qty = COUNT(*) 
    FROM tblHGP HGP, 
     OrderDetails OD, 
     tblInvoices i 
    JOIN tblCS cs ON i.INumber = cs.INumber 
    JOIN tblECI ac ON i.INumber = ac.INumber 
WHERE cs.SoldTo = HGP.ECard 
    AND issued BETWEEN '2010-09-01' AND '2010-09-30 23:59:59' 
    AND Country = 'US' 
    AND HGP.iNumber = OD.orderdetail 


SELECT [Description],Quantity,Price, Amount 
FROM 
( 
SELECT 1 AS OrderBy, 'Fees' AS [Description],@Qty AS Quantity, 1.50 AS Price , 1.5*@Qty AS Amount 
UNION ALL 
SELECT 2 AS OrderBy, 'Redep' AS [Description],NULL AS Quantity, NULL AS Price , @Points AS Amount 
UNION ALL 
SELECT 3 AS OrderBy, NULL AS [Description],NULL AS Quantity, NULL AS Price , @Points + 1.5*@Qty AS Amount 
) D 
ORDER BY OrderBy

來源

2010-10-22 16:04:20

似乎沒有用，馬丁。我沒有說明，數量，價格在我的表格中。我只是給了他們一些名字，以便更好地理解我想要做的事情。 – StealthRT 2010-10-22 16:34:31

當嘗試剛纔發佈的代碼時，我現在收到錯誤消息[消息8117，級別16，狀態1，行3 操作數數據類型varchar對求和運算符無效]。 – StealthRT 2010-10-22 16:39:09

我認爲你必須將數字數據存儲爲varchar呢？不是一個好主意。您需要從原始查詢中執行'CONVERT（int，Points）'。 – 2010-10-22 16:40:44

有關單行結果，請嘗試：

SELECT count(*) fees_quantity, 
     1.5 fees_price, 
     1.5 * count(*) fees_amount, 
     round(SUM((CONVERT(int,Points) * .1)),0)) redep_amount, 
     round(SUM((CONVERT(int,Points) * .1)),0)) + 1.5 * count(*) total_amount 
    FROM tblHGP HGP, 
     OrderDetails OD, 
     tblInvoices i 
    JOIN tblCS cs ON i.INumber = cs.INumber 
    JOIN tblECI ac ON i.INumber = ac.INumber 
WHERE cs.SoldTo = HGP.ECard 
    AND issued BETWEEN '2010-09-01' AND '2010-09-30 23:59:59' 
    AND Country = 'US' 
    AND HGP.iNumber = OD.orderdetail 
ORDER BY issued

來源

2010-10-22 16:44:05

偉大的例子，馬克！謝謝！：o） – StealthRT 2010-10-22 16:49:18

另一個快速問題。我怎樣才能把每一個設置成一個變量？ @FeesQty = fees_amount，@FeesTotal = total_amount等...？ – StealthRT 2010-10-22 17:17:32

@StealthRT，與Martin類似的方法 - 首先聲明變量，然後更改周圍的查詢項;所以'SELECT count（*）fees_quantity，1.5 fees_price，'...變成'SELECT @ fees_quantity = count（*），@ fees_price = 1.5' ...等 – 2010-10-22 17:50:56

SQL Server結合數據問題

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