在Informix的存儲過程中傳遞參數爲空

嘗試使用此存儲過程時，我不知道如何傳遞空值作爲參數。我離開了我的存儲過程的結構以及我如何嘗試使用它。在Informix的存儲過程中傳遞參數爲空

CREATE PROCEDURE SAFUP001(Padre INT, Paciente INT, AtenSol SMALLINT,  
PersSol INT, ServSol INT, ActSol INT, 
AtenEje SMALLINT, PersEje INT, ServEje INT, 
ActEje INT, Prog INT, Grup INT, 
Fecha DATETIME YEAR TO SECOND, FP INTEGER) 
RETURNING INT, INT; --Funcion, CtaCte 
DEFINE Func, x7, x8 INT; 

set debug file to "safup001.trc"; 
trace on; 

IF FP IS NULL THEN 
IF Padre IS NOT NULL THEN 
    LET x7,x8 = (SELECT A.PrevPac, A.PrevInst 
    FROM SAFUV001 A 
    WHERE A.Codigo = Padre); 
ELSE 
    LET FP = (SELECT A.FormaPago FROM SAPAV012 A 
    WHERE A.CodPacie = Paciente); 
    LET x7,x8 = (SELECT B.PagoPac, B.PagoPersona 
    FROM SABST031 B 
    WHERE B.Codigo = FP); 
END IF; 
ELSE 
    LET x7,x8 = (SELECT B.PagoPac, B.PagoPersona FROM SABST031 B 
    WHERE B.Codigo = FP); 
END IF; 

IF Fecha IS NULL THEN 
    LET Fecha = CURRENT YEAR TO SECOND; 
END IF; 

IF Grup IS NULL THEN 
    INSERT INTO SAFUT003 (Codigo, Paciente, FechaInicio, Atencion, Tipo) 
    VALUES (0, Paciente, Fecha, AtenEje, 1); 
    LET Grup = (SELECT MAX(A.Codigo) FROM SAFUT003 A 
    WHERE A.Paciente = Paciente); 
ELSE 
    IF EXISTS(SELECT * FROM SAFUT003 A WHERE A.Codigo=Grup AND 
     A.CierrePar IS NOT NULL AND A.CierreFinal IS NULL) THEN 
     UPDATE SAFUT003 SET CierrePar = NULL WHERE Codigo = Grup; 
    END IF; 
END IF; 

INSERT INTO SAFUT001 (Codigo, Paciente, Padre, Fecha, AtencionSol, 
PersonaSol, ServicioSol, ActividadSol, AtencionEje, 
PersonaEje, ServicioEje, ActividadEje, Programa, Grupo, 
PrevPac, PrevInst) 
VALUES (0, Paciente, Padre, Fecha,AtenSol, PersSol, ServSol, ActSol, 
AtenEje, PersEje, ServEje, ActEje, Prog, Grup, x7, x8); 

LET Func= (SELECT Max(A.Codigo) FROM SAFUT001 A WHERE A.Grupo = Grup); 

RETURN Func, Grup; 
END PROCEDURE;

以及執行查詢了下：

EXECUTE PROCEDURE SAFUP001 (0,781780,0,707,26,48,1,707,26,59,0,NULL,TO_DATE('2017-04-03 12:00:00','%Y-%m-%d %H:%M:%S'),14)

如果有人對如何空值傳遞給存儲過程的例子，我將不勝感激他們足夠的，因爲我有問題我的存儲過程的字段組，因爲我無法輸入以在表SAFUT003中創建組字段。

來源

2017-04-05 Cristian Saavedra

我能夠直接傳遞NULL存儲過程或使用適當的強制轉換，在Mac上使用Informix 12.10.FC5運行MacOS的塞拉利昂10.12.4這樣的：

DROP PROCEDURE IF EXISTS for_null_testing; 

CREATE PROCEDURE for_null_testing(i INTEGER, d DATETIME YEAR TO SECOND, f FLOAT, s CHAR(10)) 
    IF i IS NULL THEN RAISE EXCEPTION -746, 0, "null integer"; END IF 
    IF d IS NULL THEN RAISE EXCEPTION -746, 0, "null datetime"; END IF 
    IF f IS NULL THEN RAISE EXCEPTION -746, 0, "null float"; END IF 
    IF s IS NULL THEN RAISE EXCEPTION -746, 0, "null string"; END IF 
END PROCEDURE; 

EXECUTE PROCEDURE for_null_testing(NULL, CURRENT YEAR TO SECOND, 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(1, NULL, 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, NULL, "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, NULL); 

EXECUTE PROCEDURE for_null_testing(NULL::INTEGER, CURRENT YEAR TO SECOND, 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(1, NULL::DATETIME YEAR TO SECOND, 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, NULL::FLOAT, "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, NULL::CHAR(10)); 

EXECUTE PROCEDURE for_null_testing(CAST(NULL AS INTEGER), CURRENT YEAR TO SECOND, 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(1, CAST(NULL AS DATETIME YEAR TO SECOND), 0.0, "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, CAST(NULL AS FLOAT), "empty"); 
EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, CAST(NULL AS CHAR(10)));

運行產生：

$ sqlcmd -c -x -d stores -f null-to-spl.sql 
+ CONNECT TO 'stores' WITH CONCURRENT TRANSACTIONS 
+ DROP PROCEDURE IF EXISTS for_null_testing; 
+ CREATE PROCEDURE for_null_testing(i INTEGER, d DATETIME YEAR TO SECOND, f FLOAT, s CHAR(10)) 
    IF i IS NULL THEN RAISE EXCEPTION -746, 0, "null integer"; 
END IF 
    IF d IS NULL THEN RAISE EXCEPTION -746, 0, "null datetime"; 
END IF 
    IF f IS NULL THEN RAISE EXCEPTION -746, 0, "null float"; 
END IF 
    IF s IS NULL THEN RAISE EXCEPTION -746, 0, "null string"; 
END IF 
END PROCEDURE; 
+ EXECUTE PROCEDURE for_null_testing(NULL, CURRENT YEAR TO SECOND, 0.0, "empty"); 
SQL -746: null integer 
SQLSTATE: IX000 at null-to-spl.sql:11 
+ EXECUTE PROCEDURE for_null_testing(1, NULL, 0.0, "empty"); 
SQL -746: null datetime 
SQLSTATE: IX000 at null-to-spl.sql:12 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, NULL, "empty"); 
SQL -746: null float 
SQLSTATE: IX000 at null-to-spl.sql:13 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, NULL); 
SQL -746: null string 
SQLSTATE: IX000 at null-to-spl.sql:14 
+ EXECUTE PROCEDURE for_null_testing(NULL::INTEGER, CURRENT YEAR TO SECOND, 0.0, "empty"); 
SQL -746: null integer 
SQLSTATE: IX000 at null-to-spl.sql:16 
+ EXECUTE PROCEDURE for_null_testing(1, NULL::DATETIME YEAR TO SECOND, 0.0, "empty"); 
SQL -746: null datetime 
SQLSTATE: IX000 at null-to-spl.sql:17 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, NULL::FLOAT, "empty"); 
SQL -746: null float 
SQLSTATE: IX000 at null-to-spl.sql:18 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, NULL::CHAR(10)); 
SQL -746: null string 
SQLSTATE: IX000 at null-to-spl.sql:19 
+ EXECUTE PROCEDURE for_null_testing(CAST(NULL AS INTEGER), CURRENT YEAR TO SECOND, 0.0, "empty"); 
SQL -746: null integer 
SQLSTATE: IX000 at null-to-spl.sql:21 
+ EXECUTE PROCEDURE for_null_testing(1, CAST(NULL AS DATETIME YEAR TO SECOND), 0.0, "empty"); 
SQL -746: null datetime 
SQLSTATE: IX000 at null-to-spl.sql:22 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, CAST(NULL AS FLOAT), "empty"); 
SQL -746: null float 
SQLSTATE: IX000 at null-to-spl.sql:23 
+ EXECUTE PROCEDURE for_null_testing(2, CURRENT YEAR TO SECOND, 3.14159, CAST(NULL AS CHAR(10))); 
SQL -746: null string 
SQLSTATE: IX000 at null-to-spl.sql:24 
$

在每種情況下，都會產生正確的異常。在過去很久以前，在沒有限定符的情況下可能會傳遞NULL，但其中一個集合應該工作，除非你有一個真正的Informix的古老版本。

來源

2017-04-05 20:19:55

在Informix的存儲過程中傳遞參數爲空

回答

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