4
我有一個接受包含XML文件的ZIP文件的servlet。我想閱讀這些XML文件的內容,但我得到一個java.io.IOException:流關閉。閱讀ZipEntry中的字符串:java.io.IOException:Stream已關閉
我得到的ZIP像這樣:
private byte[] getZipFromRequest(HttpServletRequest request) throws IOException {
byte[] body = new byte[request.getContentLength()];
new DataInputStream(request.getInputStream()).readFully(body);
return body;
}
我看它像這樣:
public static void readZip(byte[] zip) throws IOException {
ByteArrayInputStream in = new ByteArrayInputStream(zip);
ZipInputStream zis = new ZipInputStream(in);
ZipEntry entry;
while ((entry = zis.getNextEntry()) != null) {
System.out.println(String.format("Entry: %s len %d", entry.getName(), entry.getSize()));
BufferedReader br = new BufferedReader(new InputStreamReader(zis, "UTF-8"));
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
br.close();
}
zis.close();
}
輸出:
Entry: file.xml len 3459
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<test>
correct content of my xml file
</test>
java.io.IOException: Stream closed
at java.util.zip.ZipInputStream.ensureOpen(ZipInputStream.java:67)
at java.util.zip.ZipInputStream.getNextEntry(ZipInputStream.java:116)
at util.ZipHelper.readZip(ZipHelper.java:26)
我的問題
爲什麼我在這條線上得到這個豁免?
while ((entry = zis.getNextEntry()) != null) {
我錯過了什麼?
就是這樣。我應該將該聲明從循環中取出並關閉它嗎?有沒有更好的方法來做到這一點? – Tim