2016-11-26 54 views
1

我試圖從測量中獲取格式化的值,將單位作爲兩個單獨的字符串。我已經寫了下面的功能來做到這一點。我正在努力處理模板的擴展的函數格式。如何從測量中獲取格式化的值和單位

這不起作用:

func getFormattedValueAndUnitFromMeasurement(measurement: Measurement<Unit>) 

下面的作品,但後來我需要定義功能爲每個單位類型。

func getFormattedValueAndUnitFromMeasurement(measurement: Measurement<UnitLength>) 

這是我使用的代碼。

var diameter: Measurement<UnitLength> = Measurement<UnitLength>(value: 13, unit: .inches) 

let diameterFormatter = MeasurementFormatter() 
diameterFormatter.unitStyle = .medium 
diameterFormatter.unitOptions = .providedUnit // .natural 
diameterFormatter.numberFormatter.generatesDecimalNumbers = true 
diameterFormatter.numberFormatter.maximumFractionDigits = 1 

    // Get the formatted text for the value and the units 
let diameterText = diameterFormatter.getFormattedValueAndUnitFromMeasurement(measurement: diameter) 


extension MeasurementFormatter { 
    func getFormattedValueAndUnitFromMeasurement(measurement: Measurement<Unit>) -> (valueString: String, unitString: String) 
    { 
     // Number Formatter 
     let numberFormatter = self.numberFormatter 

     // This assumes the number is going to be displayed in the provided units. Ok for now 
     let numberString = numberFormatter?.string(from: NSNumber (value: measurement.value)) 

     // Figure out just the units of the string 
     var units: String = self.string(for: measurement)! 

     if (units.hasPrefix(numberString!)) { 
      units.removeSubrange((numberString?.startIndex)! ..< (numberString?.index((numberString?.startIndex)!, offsetBy: (numberString?.characters.count)!))!) 
     } 

     return (numberString!, units) 
    } 
} 

回答

0

Measurement<Unit>Measurement<UnitLength>被認爲是兩種不同的類型,如StringInt。您應該使用泛型來處理所需的類型,例如

func getFormattedValueAndUnitFromMeasurement<T>(measurement: Measurement<T>)  
               -> (valueString: String, unitString: String) 
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