在PHP中使用數組，如何總是通過key2更改key1或通過key1更改key2？

Question

我以前的代碼是蘭特，這無關我目前的意圖，這是更換每當我找到一個值，該陣列的其他價值。

$myWords=array(
    array('funny','sad'), 
    array('fast','slow'), 
    array('beautiful','ugly'), 
    array('left','right'), 
    array('5','five'), 
    array('strong','weak') 
); 

$mycontentmixed = rewrite3($myVar, $myWords); 
$myVar = 'This girl is very funny and fast and kick to left'; 

當系統發現包含在陣列中的任意鍵的值，隨時切換到它的另一個值，我有這些系統準備好了，但它確實蘭特，有時落在上找到相同的密鑰，並在50％的情況下，它不值，我總是想改變。

我想更改爲：

output: 'This girl is very sad and slow and kick to right'; 

或者，如果你發現另一個關鍵：

$myVar = 'This girl is very sad and slow and kick to right'; 

切換到：

Output: 'This girl is very funny and fast and kick to left'; 

當的關鍵之一是在發現$ myVar變量總是爲另一個鍵進行交換。

謝謝。

Answer 1

Barmar是正確的，strtr()是這個任務的正確功能。由於$myWords陣列的結構不適用於strtr()，所以在準備過程中需要6次函數調用。如果$myWords與strtr()一起聲明，則可以避免/減少這六個呼叫。

從本質上講，這可以是一個單功能溶液，並應被用來代替迭代條件檢查然後str_replace()。

方法：

$myWords=array(
    array('funny','sad'), 
    array('fast','slow'), 
    array('beautiful','ugly'), 
    array('left','right'), 
    array('5','five'), 
    array('strong','weak') 
); 

// prepare values from $myWords for use with strtr() 
$replacements=array_combine(array_column($myWords,0),array_column($myWords,1))+ 
       array_combine(array_column($myWords,1),array_column($myWords,0)); 
echo strtr($myVar,$replacements); 

輸入/輸出：

$myVar='This girl is very funny and fast and kick to left'; 
//outputs: This girl is very sad and slow and kick to right 

    $myVar='This girl is very sad and slow and kick to right'; 
//outputs: This girl is very funny and fast and kick to left 

    $myVar='I was beautiful and strong when I was 5 now I\'m ugly and weak'; 
//outputs: I was ugly and weak when I was five now I'm beautiful and strong 

唯一額外的步驟是數組製備。我無法使用array_merge()，因爲數字字符串（5）在此過程中被清理。這是+串聯的原因。

Answer 2

此代碼將做到這一點：

$myWords=array(
array('funny','sad') 
,array('fast','slow') 
,array('beautiful','ugly') 
,array('left','right') 
,array('5','five') 
,array('strong','weak') 
); 


$myVar = 'This girl is very funny and fast and kick to left'; 

foreach ($myWords as $key => $val) { 
    if (strpos($myVar, $val[0]) !== FALSE) { 
    $myVar = str_replace($val[0], $val[1], $myVar); 
    } 
    else { 
    $myVar = str_replace($val[1], $val[0], $myVar); 
    } 
} 
echo $myVar; 

希望這有助於。