獲取URL

Question

一個斜線後，我有一個簡單的URL像這樣

http://siteurl.com/2014/09/net-special-report-9ice-father-of-3-successful-entertainer-with-eyes-on-house-of-reps/

我怎麼能是

結尾的斜線之後得到的最後一個值的值

net-special-report-9ice-father-of-3-success-entertainer-with-eyes-on-house-of-reps

任何想法。謝謝

Answer 1

使用拆分來做到這一點。如下所示：

str = "http://siteurl.com/2014/09/net-special-report-9ice-father-of-3-successful-entertainer-with-eyes-on-house-of-reps/" 
#=> "http://siteurl.com/2014/09/net-special-report-9ice-father-of-3-successful-entertainer-with-eyes-on-house-of-reps/" 
a = str.split('/') 
#=> ["http:", "", "siteurl.com", "2014", "09", "net-special-report-9ice-father-of-3-successful-entertainer-with-eyes-on-house-of-reps"] 
a.last 
#=> "net-special-report-9ice-father-of-3-successful-entertainer-with-eyes-on-house-of-reps"