1
我有一個標籤,我將放入不同大小的內容。我想知道我需要製作標籤的程度有多高,以便我可以調整窗口的大小,使其可以保持不同的內容大小。我有一個策略,但它應該是更復雜。Tkinter標籤的高度以適應內容
我希望將標籤設置爲指定寬度和wraplength:
l = Label(root)
l['width'] = 30
l['wraplength'] = 244
l['text'] = "testing this"
現在我要查詢的標籤找到多少行使用。 l ['height']保持爲0,所以我能夠想到的最好的方法是使用l.winfo_height()並將像素的高度轉換爲使用的行數。 dir(l)似乎沒有直接給我提供信息,但是這種策略對於字體變化和其他變化是脆弱的。
有什麼建議嗎?
更新:使用布賴恩·奧克利的建議(這是類似於我在Usenet了)我有以下近似的解決方案(需要拋光,比如沒有考慮到,在空白標籤休息帳戶):
import Tkinter as Tk
import tkFont
import random
import sys
def genstr (j):
rno = random.randint(4,50)
ret_val = str(j) + ":"
for i in range (0, rno):
ret_val += "hello" + str(i)
return ret_val
def gendata (lh):
ret_val = []
for i in range(0,lh):
ret_val.append (genstr (i))
return ret_val
data = gendata (100)
root = Tk.Tk()
font = tkFont.Font(family='times', size=13)
class lines:
def __init__ (self):
self.lastct = 1 # remember where the cutoff was last work from there
def count (self, text, cutoff = 400):
global font
no_lines = 1
start_idx = 0
idx = self.lastct
while True:
if idx > len (text):
idx = len (text)
# shrink from guessed value
while font.measure (text[start_idx:idx - 1]) > cutoff:
if idx <= start_idx:
print "error"
sys.exit()
else:
idx -= 1
self.lastct = idx - start_idx # adjust since was too big
# increase from guessed value (note: if first shrunk then done)
while (idx < len (text)
and font.measure (text[start_idx:idx]) < cutoff):
idx += 1
self.lastct = idx - start_idx # adjust since was too small
# next line has been determined
print "*" + text[start_idx:idx-1] + "*"
if idx == len(text) and font.measure (text[start_idx:]) < cutoff:
return no_lines
elif idx == len(text):
return no_lines + 1
else:
no_lines += 1
start_idx = idx - 1
idx = start_idx + self.lastct
lin = lines()
for i in range(0,len(data)):
lin.count(data[i], 450)
for i in range(0,min(len(data),10)):
l = Tk.Label(root)
l.pack()
l['text'] = data[i]
print i
no = lin.count (data[i], 450)
print "computed lines", no
l['width'] = 50
l['justify'] = Tk.LEFT
l['anchor'] = 'w'
l['wraplength'] = 450
l['padx']=10
l['pady'] = 5
l['height'] = no
l['font'] = font
if i % 2 == 0:
l['background'] = 'grey80'
else:
l['background'] = 'grey70'
root.mainloop()