我需要建立一個const char
其他const char
的字符串?如何將const char連接到const char?
const char *sql = "";
const char *sqlBuild = "";
for(int i=0; i < ac_count; ++i) {
if (![sqlBuild isEqualToString:@""]) {
sqlBuild = [sqlBuild stringByAppendingString:
[NSString stringWithUTF8String:@" UNION "]];
}
sql = [[NSString stringWithFormat:
@"select sum(price) from tmp%d where due >= date() and due <= '%@'",
i, strDBDate] cStringUsingEncoding:NSUTF8StringEncoding];
sqlBuild = [sqlBuild stringByAppendingString:
[NSString stringWithUTF8String:sql]];
}
//execute sql
我已經嘗試過幾次,但不能完全正確,繼承人是我的最後一次嘗試。正如你可以看到我試圖建立一個SQL語句。
我哪裏錯了?
編輯 - 我正在使用不喜歡NSString的sql lite,見下文。
- (NSString*)getCategoryDesc:(int)pintCid {
NSString *ret = @"";
const char *sql = "select category from categories where cid = ?";
sqlite3 *database;
int result = sqlite3_open([[General getDBPath] UTF8String], &database);
if(result != SQLITE_OK)
{
DLog(@"Could not open db.");
}
sqlite3_stmt *statementTMP;
int error_code = sqlite3_prepare_v2(database, sql, -1, &statementTMP, NULL);
if(error_code == SQLITE_OK) {
sqlite3_bind_int(statementTMP, 1, pintCid);
if (sqlite3_step(statementTMP) == SQLITE_ROW) {
ret = [[NSString alloc] initWithUTF8String:
(char *)sqlite3_column_text(statementTMP, 1)];
}
}
sqlite3_finalize(statementTMP);
sqlite3_close(database);
return [ret autorelease];
}
我使用SQLite,見上面,它不喜歡的NSString – Jules
就是爲什麼我說,執行[sqlStatement UTF8String],它返回一個C風格的字符串。 – Tommy