2017-05-30 164 views
0

我在創建登錄和註冊java時遇到問題。我能夠創建一個用戶,但它返回錯誤。它返回JSON +錯誤。 這是JSON和錯誤,當我嘗試登錄:在Android中無法將java.lang.String轉換爲JSONObject登錄和註冊

D/RegisterActivity: Login Response: login.php 
       DB_Connect.php 
        Config.php 
       {"error":false,"uid":"592da509e15a88.38765516","user":{"name":"P","email":"p","created_at":"2017-05-30 17:59:53"}} 

W/System.err: org.json.JSONException: Value login.php of type java.lang.String cannot be converted to JSONObject 
W/System.err:at activity.LoginActivity$3.onResponse(LoginActivity.java:125) 
W/System.err:at activity.LoginActivity$3.onResponse(LoginActivity.java:117) 

這是login.java

public class LoginActivity extends Activity { 
private static final String TAG = RegisterActivity.class.getSimpleName(); 
private Button btnLogin; 
private Button btnLinkToRegister; 
private EditText inputEmail; 
private EditText inputPassword; 
private ProgressDialog pDialog; 
private SessionManager session; 
private SQLiteHandler db; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_login); 

    inputEmail = (EditText) findViewById(R.id.email); 
    inputPassword = (EditText) findViewById(R.id.password); 
    btnLogin = (Button) findViewById(R.id.btnLogin); 
    btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen); 

    // Progress dialog 
    pDialog = new ProgressDialog(this); 
    pDialog.setCancelable(false); 

    // SQLite database handler 
    db = new SQLiteHandler(getApplicationContext()); 

    // Session manager 
    session = new SessionManager(getApplicationContext()); 

    // Check if user is already logged in or not 
    if (session.isLoggedIn()) { 
     // User is already logged in. Take him to main activity 
     Intent intent = new Intent(LoginActivity.this, MainActivity.class); 
     startActivity(intent); 
     finish(); 
    } 

    // Login button Click Event 
    btnLogin.setOnClickListener(new View.OnClickListener() { 

     public void onClick(View view) { 
      String email = inputEmail.getText().toString().trim(); 
      String password = inputPassword.getText().toString().trim(); 

      // Check for empty data in the form 
      if (!email.isEmpty() && !password.isEmpty()) { 
       // login user 
       checkLogin(email, password); 
      } else { 
       // Prompt user to enter credentials 
       Toast.makeText(getApplicationContext(), 
         "Please enter the credentials!", Toast.LENGTH_LONG) 
         .show(); 
      } 
     } 

    }); 

    // Link to Register Screen 
    btnLinkToRegister.setOnClickListener(new View.OnClickListener() { 

     public void onClick(View view) { 
      Intent i = new Intent(getApplicationContext(), 
        RegisterActivity.class); 
      startActivity(i); 
      finish(); 
     } 
    }); 

} 

/** 
* function to verify login details in mysql db 
* */ 
private void checkLogin(final String email, final String password) { 
    // Tag used to cancel the request 
    String tag_string_req = "req_login"; 

    pDialog.setMessage("Logging in ..."); 
    showDialog(); 

    StringRequest strReq = new StringRequest(Method.POST, 
      AppConfig.URL_LOGIN, new Response.Listener<String>() { 

     @Override 
     public void onResponse(String response) { 
      Log.d(TAG, "Login Response: " + response.toString()); 
      hideDialog(); 

      try { 
       JSONObject jObj = new JSONObject(response); 
       boolean error = jObj.getBoolean("error"); 

       // Check for error node in json 
       if (!error) { 
        // user successfully logged in 
        // Create login session 
        session.setLogin(true); 

        // Now store the user in SQLite 
        String uid = jObj.getString("uid"); 

        JSONObject user = jObj.getJSONObject("user"); 
        String name = user.getString("name"); 
        String email = user.getString("email"); 
        String created_at = user 
          .getString("created_at"); 

        // Inserting row in users table 
        db.addUser(name, email, uid, created_at); 

        // Launch main activity 
        Intent intent = new Intent(LoginActivity.this, 
          MainActivity.class); 
        startActivity(intent); 
        finish(); 
       } else { 
        // Error in login. Get the error message 
        String errorMsg = jObj.getString("error_msg"); 
        Toast.makeText(getApplicationContext(), 
          errorMsg, Toast.LENGTH_LONG).show(); 
       } 
      } catch (JSONException e) { 
       // JSON error 
       e.printStackTrace(); 
       Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show(); 
      } 

     } 
    }, new Response.ErrorListener() { 

     @Override 
     public void onErrorResponse(VolleyError error) { 
      Log.e(TAG, "Login Error: " + error.getMessage()); 
      Toast.makeText(getApplicationContext(), 
        error.getMessage(), Toast.LENGTH_LONG).show(); 
      hideDialog(); 
     } 
    }) { 

     @Override 
     protected Map<String, String> getParams() { 
      // Posting parameters to login url 
      Map<String, String> params = new HashMap<String, String>(); 
      params.put("email", email); 
      params.put("password", password); 

      return params; 
     } 

    }; 

    // Adding request to request queue 
    AppController.getInstance().addToRequestQueue(strReq, tag_string_req); 
} 

private void showDialog() { 
    if (!pDialog.isShowing()) 
     pDialog.show(); 
} 

private void hideDialog() { 
    if (pDialog.isShowing()) 
     pDialog.dismiss(); 
}} 

的login.php代碼:

<?php 
require_once 'include/DB_Functions.php'; 
$db = new DB_Functions(); 

// json response array 
$response = array("error" => FALSE); 

if (isset($_POST['email']) && isset($_POST['password'])) { 

// receiving the post params 
$email = $_POST['email']; 
$password = $_POST['password']; 

// get the user by email and password 
$user = $db->getUserByEmailAndPassword($email, $password); 

if ($user != false) { 
    // use is found 
    $response["error"] = FALSE; 
    $response["uid"] = $user["unique_id"]; 
    $response["user"]["name"] = $user["NAME"]; 
    $response["user"]["email"] = $user["email"]; 
    $response["user"]["created_at"] = $user["created_at"]; 
    echo json_encode($response); 
} else { 
    // user is not found with the credentials 
    $response["error"] = TRUE; 
    $response["error_msg"] = "Login credentials are wrong. Please try again!"; 
    echo json_encode($response); 
} 
} else { 
// required post params is missing 
$response["error"] = TRUE; 
$response["error_msg"] = "Required parameters email or password is missing!"; 
echo json_encode($response); 
} 
?> 

我不得不花費數小時對此,任何人都可以將我指向正確的方向?謝謝

+0

我可以在日誌中看到,響應比json多,也有php文件名,我認爲這是JSONException。你從反應中只取得了json。 – ARP

+0

實際的登錄響應是什麼? >>> Log.d(TAG,「登錄響應:」+ response.toString()); //發佈完整的login.php代碼 – FAT

+0

我發佈了完整的login.java和完整的login.php @FAT –

回答

1

登錄響應:login.php DB_Connect.php Config.php {"error":false,"uid":"592da509e15a88.38765516","user":{"name‌​":"P","email":"p","c‌​reated_at":"2017-05-‌​30 17:59:53"}}

根據您的連接響應message,它似乎完全wrong

您的回覆不是JSON格式化string這就是爲什麼它無法從此字符串創建JSONObject

確保您的迴應只有JSONObject包含:

{"error":false,"uid":"592da509e15a88.38765516","user":{"name‌​":"P","email":"p","c‌​reated_at":"2017-05-‌​30 17:59:53"}}

從響應消息中刪除不必要的字符串"login.php DB_Connect.php Config.php"。檢查你的服務器端代碼,爲什麼它添加字符串"login.php DB_Connect.php Config.php"JSONObject

我認爲這將解決您的問題。

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