在網站上登錄後顯示用戶名

Question

我正在設計一個帶有登錄頁面的網站。登錄部分和從數據庫抓取工作正常。但我想在登錄後在主頁上顯示用戶名。我使用session_start（）。但用戶名不顯示。我在這裏查了類似的問題，但沒有一個是我的答案。以下是代碼： PHP代碼：

$email = mysqli_real_escape_string($con,$_POST['user']); 
$pass = mysqli_real_escape_string($con,$_POST['pass']); 
$sel_user = "select * from admins where email='$email' AND password='$pass'"; 
$run_user = mysqli_query($con, $sel_user); 
$check_user = mysqli_num_rows($run_user); 
if($check_user>0) 
{ 
$_SESSION['email']=$email 
echo "<script>window.open('index2.html','_self')</script>"; 
} 
else { 
echo "<script>alert('Email or password is not correct, try again!')</script>"; 
} 

index2.html：

<?php 
     session_start(); 
?> 
    <div class="inline-block"> 
           <h5 class="no-margin"> Welcome </h5> 
           <h4 class="no-margin"> <?php echo $_SESSION['email']; ?> </h4> 
           <a class="btn user-options sb_toggle"> 
            <i class="fa fa-cog"></i> 
           </a> 
          </div> 

Answer 1

嘗試以下代碼：

第一代碼：

session_start(); 
$email = mysqli_real_escape_string($con,$_POST['user']); 
$pass = mysqli_real_escape_string($con,$_POST['pass']); 
$sel_user = "select * from admins where email='$email' AND password='$pass'"; 
$run_user = mysqli_query($con, $sel_user); 
$check_user = mysqli_num_rows($run_user); 
if($check_user>0) 
{ 
    $_SESSION['email']=$email 
    echo "<script>window.open('index2.html','_self')</script>"; 
} 
else { 
    echo "<script>alert('Email or password is not correct, try again!')</script>"; 
} 

index2.php：

<?php session_start(); ?> 
<div class="inline-block"> 
    <h5 class="no-margin"> Welcome </h5> 
    <h4 class="no-margin"> <?php echo $_SESSION['email']; ?> </h4> 
    <a class="btn user-options sb_toggle"> 
     <i class="fa fa-cog"></i> 
    </a> 
</div> 

它應該工作。