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我想用下面的代碼上傳文件:當我執行的方法,它需要一個上傳文件內容需要很長的時間
url = "/folder/sub/interface?"
connection = httplib.HTTPConnection('www.mydomain.com')
def sendUpload(self):
fields = []
file1 = ['file1', '/home/me/Desktop/sometextfile.txt']
f = open(file1[1], 'r')
file1.append(f.read())
files = [file1]
content_type, body = self.encode_multipart_formdata(fields, files)
myheaders['content-type'] = content_type
myheaders['content-length'] = str(len(body))
upload_data = urllib.urlencode({'command':'upload'})
self.connection.request("POST", self.url + upload_data, {}, myheaders)
response = self.connection.getresponse()
if response.status == 200:
data = response.read()
self.connection.close()
print data
的encode_multipart_formdata()來自http://code.activestate.com/recipes/146306/
很長時間才能完成。事實上,我不認爲它會結束..在網絡監視器上,我看到數據傳輸,但方法並沒有結束...
這是爲什麼?我應該在什麼地方設置暫停嗎?