在SQL Server 2008中計算到期日期

第一批付款日期是加入日期。客戶必須支付10期分期付款。每個月的每一期付款。因此，11個月後，客戶有資格購買節省的產品。所以到期日是從加入日起11個月。實例加入日期：12 /九月/ 2016 到期日：12 /七月/ 2017年在SQL Server 2008中計算到期日期

如果客戶預定的日期或任何一天在當月到期日不擴展其他到期日被延長內支付。

Scenario 1: Pays on time 
------------------------ 

Joining date: 12/Sep/2016 
Expected output: 12/Jul/2017

 
    Joining Date 12/Sep/2016 

Inst No Payment Date Actual Date payment Considered Month 
1  12/Sep/2016 12/Sep/2016 Sep 2016 
2  05/Oct/2016 12/Oct/2016 Oct 2016 
3  21/Nov/2016 12/Nov/2016 Nov 2016 
4  12/Dec/2016 12/Dec/2016 Dec 2016 
5  02/Jan/2017 12/Jan/2017 Jan 2017 
6  02/Feb/2017 12/Feb/2017 Feb 2017 
7  06/Mar/2017 12/Mar/2017 Mar 2017 
8  06/Apr/2017 12/Apr/2017 Apr 2017 
9  01/May/2017 12/May/2017 May 2017 
10  07/Jun/2017 12/Jun/2017 Jun 2017 

     Maturity Date 12/Jul/2017

Scenario1

Scenario 2: when payments paid with delay 
----------------------------------------- 

Joining date: 12/Sep/2016 
Expected output: 12/Sep/2017

Scenario2

 Joining Date 12/Sep/2016 

Inst No Payment Date Actual Date Payment Considered Month 
1  12/Sep/2016  12/Sep/2016 Sep 2016 
2  05/Oct/2016  12/Oct/2016 Oct 2016 
3  21/Nov/2016  12/Nov/2016 Nov 2016 
4  02/Feb/2017  12/Dec/2016 Feb 2017 
5  02/Feb/2017  12/Jan/2017 Mar 2017 
6  06/Mar/2017  12/Feb/2017 Apr 2017 
7  06/Mar/2017  12/Mar/2017 May 2017 
8  01/Jun/2017  12/Apr/2017 Jun 2017 
9  01/Jun/2017  12/May/2017 Jul 2017 
10  07/Aug/2017  12/Jun/2017 Aug 2017 

     Maturity Date 12/Sep/2017

來源

2017-10-16 Susanna Floora

發佈SQL和表結構和樣本數據將幫助我們得到一個解決方案，規則更詳細的說明會幫助，從我所看到的規則看來是每月錯過的付款延長一個月。 – RegBes

你的問題不清楚的你想達到的目標。但是，從我的兩個例子中可以看出，到期日應該比分期支付的延遲多數月。

即使你的提琴手方案也不清楚。有了這一點了解，我想出了下面的T-SQL來解決你的問題：

-- Schema generation 
CREATE TABLE [dbo].[Payment](
    [InsNo] [int] PRIMARY KEY NOT NULL, 
    [ReceiptDate] [datetime] NULL, 
    [ScheduledDate] [datetime] NULL, 
    [ConsideredMonth] DATETIME NULL, 
) ON [PRIMARY] 

GO 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(1, '2016-09-12 00:00:00', '2016-09-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(2, '2016-10-05 00:00:00', '2016-10-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(3, '2016-11-21 00:00:00', '2016-11-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(4, '2017-02-02 00:00:00', '2016-12-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(5, '2017-02-02 00:00:00', '2016-01-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(6, '2017-02-02 00:00:00', '2016-02-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(7, '2017-03-06 00:00:00', '2016-03-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(8, '2017-03-06 00:00:00', '2016-04-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(9, '2017-06-01 00:00:00', '2016-05-12 00:00:00'); 

INSERT INTO [Payment]([InsNo], [ReceiptDate], [ScheduledDate]) 
    VALUES(10, '2017-06-01 00:00:00', '2016-06-12 00:00:00'); 

GO 

-- Solution using Cursor   
DECLARE @receiptDate DATETIME 
     ,@lastInstForDate DATETIME 
DECLARE @insNo INT 

DECLARE _paymentsCursor CURSOR FAST_FORWARD 
FOR 
    SELECT p.InsNo 
      ,p.ReceiptDate 
    FROM Payment p 
    ORDER BY 
      p.InsNo 

OPEN _paymentsCursor 

FETCH NEXT FROM _paymentsCursor INTO 
    @insNo, @receiptDate 
WHILE @@FETCH_STATUS = 0 
BEGIN 
    SELECT @lastInstForDate = p.ConsideredMonth 
    FROM Payment p 
    WHERE p.InsNo = @insNo - 1 

    IF DATEADD(MONTH ,1 ,@lastInstForDate) > @receiptDate 
     UPDATE Payment 
     SET ConsideredMonth  = DATEADD(MONTH ,1 ,@lastInstForDate) 
     WHERE InsNo = @insNo 
    ELSE 
     UPDATE Payment 
     SET ConsideredMonth = CAST(CAST(YEAR(ReceiptDate) AS VARCHAR(4)) + RIGHT('0' + CAST(MONTH(ReceiptDate) AS VARCHAR(2)) ,2) + '01' AS DATETIME) 
     WHERE InsNo = @insNo 

    FETCH NEXT FROM _paymentsCursor INTO 
     @insNo, @receiptDate 
END 

CLOSE _paymentsCursor 
DEALLOCATE _paymentsCursor 


DECLARE @lastPaymentDate DATETIME 

DECLARE @maturityDate DATETIME 
SELECT @maturityDate = DATEADD(month, 1, MAX(p.ConsideredMonth)), @lastPaymentDate = MAX(p.ReceiptDate) FROM dbo.Payment p 
SET @maturityDate = CAST(CAST(YEAR(@maturityDate) AS VARCHAR(4)) + RIGHT('0' + CAST(MONTH(@maturityDate) AS VARCHAR(2)) ,2) + RIGHT('0' + CAST(DAY(@lastPaymentDate) AS VARCHAR(2)) ,2) AS DATETIME) 
SET @maturityDate = DATEADD(DAY, 1, @maturityDate) 

SELECT @maturityDate

來源

2017-10-27 05:07:04 Nagesh

你可以使用這個公式。

select DATEADD(DAY, 
       DATEPART(DAY,(MIN([Actual Date]))) - DATEPART(DAY,(MAX([Payment Date]))), 
        DATEADD(MONTH, 
         (11 - COUNT(*)) 
         , MAX([Payment Date]))) 
from @InstalmentTable

來源

2017-10-16 11:02:28

試試這個 -

SELECT MATURITY_DATE = CASE WHEN MAX([ReceiptDate]) <= DATEADD (MM , 9, '2016-09-12 00:00:00') 
         THEN DATEADD (MM , 10, '2016-09-12 00:00:00') 
         ELSE DATEADD (MM , 2, MAX([ReceiptDate])) END 
FROM [dbo].[Payment];

來源

2017-10-16 11:38:44

在SQL Server 2008中計算到期日期

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