PHP打印使用While循環和陣列返回的所有值

我遇到以下只返回最後1條記錄的代碼的問題。PHP打印使用While循環和陣列返回的所有值

使用while循環我能夠檢索所有的值並將其添加到數組，併爲每個循環得到它，但我無法返回所有的值。

一旦調用此函數只返回最後1條記錄。任何人都可以請幫我修復這個代碼，它會返回所有的值。由於

echo gettradinghours("54"); 
function gettradinghours($storeid){ 

    $select_tradinghours = mysqli_query("SELECT * FROM `tradinghours` where `storeid`='54' ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY');"); 

$atradinghours = array(); 
while($fetch_tradinghours = mysqli_fetch_array($select_tradinghours)){ 
    array_push($atradinghours, $fetch_tradinghours['openday']. ' ' .$fetch_tradinghours['starttime']. ' - ' .$fetch_tradinghours['endtime']); 
    } 
    foreach($atradinghours as $atradinghoursr){ 
     $getval = $atradinghoursr; 
    } 

    return $getval; 
}

來源

2014-10-31 lock

是的，你是在foreach循環完成後返回值，所以它重新在$ atradinghours數組轉換最後一個值 – Choco 2014-10-31 11:32:59

@ lock，我發佈了您的問題的答案，您只需在$ getval的forloop中添加括號即可。所以它會是$ getval []而不是$ getval並且您的問題將得到解決。 – 2014-10-31 11:34:56

首先要指出的是，mysqli_query()的第一個參數是你需要餵它與mysqli連接。
其次，你不需要另一個foreach循環。只需在while內部推入值，然後最後返回該值容器。

 
function gettradinghours($storeid){ 
    // 1st point! connection! 
    $connection = mysqli_connect('localhost', 'username', 'password', 'database_base'); 
    $select_tradinghours = mysqli_query($connection, "SELECT * FROM `tradinghours` WHERE `storeid`='54' ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY')"); 

    $atradinghours = array(); 
    // no need for that array push thing, just push it normally and return in the end 
    while($fetch_tradinghours = mysqli_fetch_array($select_tradinghours)){ 
     $atradinghours[] = $fetch_tradinghours['openday']. ' ' .$fetch_tradinghours['starttime']. ' - ' .$fetch_tradinghours['endtime']; 
    } 
    return $atradinghours; // return the gathered/pushed values 
} 

print_r(gettradinghours("54")); // use the function

最後不使用你的參數，你自己的函數中覓食。並使用準備好的語句。

 
function gettradinghours($storeid){ 

    // connection! 
    $connection = mysqli_connect('localhost', 'username', 'password', 'database_base'); 
    // use prepared statements! 
    $stmt = $connection->prepare(" 
     SELECT openday, starttime, endtime FROM `tradinghours` WHERE`storeid` = ? 
     ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY') 
    "); 
    $stmt->bind_param('i', $storeid); // bind the paramter input! 
    $stmt->execute(); 
    $stmt->bind_result($openday, $starttime, $endtime); 

    $atradinghours = array(); 
    while($stmt->fetch()) { // as usual push the values 
     $atradinghours[] = $openday. ' ' .$starttime. ' - ' .$endtime; 
    } 

    return $atradinghours; // return the gathered values 
} 

print_r(gettradinghours(54));

旁註：

如果你不希望這樣的結果（數組），你可以建立一個字符串，而不是：到底

$atradinghours = ''; 
while($stmt->fetch()) { // as usual push the values 
    $atradinghours .= $openday. ' ' .$starttime. ' - ' .$endtime . '<br/>'; 
}

然後，你現在可以回聲正確一個字符串：

echo gettradinghours(54);

來源

2014-10-31 11:34:00 Ghost

rning：mysq li_stmt :: bind_result（）：綁定變量的數量不匹配準備語句中的字段數 – lock 2014-10-31 11:41:58

@lock我正在做一些修訂，再次檢查答案 – Ghost 2014-10-31 11:45:31

作爲「數組」返回的輸出 – lock 2014-10-31 11:48:06

爲什麼又一個的foreach

function gettradinghours($storeid){ 
      $select_tradinghours = mysqli_query("SELECT * FROM `tradinghours` where `storeid`='54' ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY');"); 

      $atradinghours = array(); 
      while($fetch_tradinghours = mysqli_fetch_array($select_tradinghours)){ 
       array_push($atradinghours, $fetch_tradinghours['openday']. ' ' .$fetch_tradinghours['starttime']. ' - ' .$fetch_tradinghours['endtime']); 
      } 

    return $atradinghours; 
}

來源

2014-10-31 11:32:38 senK

您通過數組循環和返回的最後一個數組元素，

在哪裏，只要你想整個陣列。

foreach($atradinghours as $atradinghoursr){ 
       $getval = $atradinghoursr; 
      }

只應

$getval = $atradinghours; 
return $atradinghours;

來源

2014-10-31 11:33:34 Pupil

（1）返回的數組：

function gettradinghours($storeid){ 
       $getval = array(); 
       $select_tradinghours = mysqli_query("SELECT * FROM `tradinghours` where `storeid`='54' ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY');"); 

       $atradinghours = array(); 
       while($fetch_tradinghours = mysqli_fetch_array($select_tradinghours)){ 
        array_push($atradinghours, $fetch_tradinghours['openday']. ' ' .$fetch_tradinghours['starttime']. ' - ' .$fetch_tradinghours['endtime']); 
       } 
       foreach($atradinghours as $atradinghoursr){ 
        $getval[] = $atradinghoursr; 
       } 
     return $getval; 
    }

（2）返回的字符串：

function gettradinghours($storeid){ 
       $getval = ''; 
       $select_tradinghours = mysqli_query("SELECT * FROM `tradinghours` where `storeid`='54' ORDER BY FIELD(openday, 'MONDAY', 'TUESDAY', 'WEDNESDAY', 'THURSDAY', 'FRIDAY', 'SATURDAY', 'SUNDAY');"); 

       $atradinghours = array(); 
       while($fetch_tradinghours = mysqli_fetch_array($select_tradinghours)){ 
         $getval.= $fetch_tradinghours['openday']. ' ' .$fetch_tradinghours['starttime']. ' - ' .$fetch_tradinghours['endtime']; 
       } 

     return $getval; 
    }

來源

2014-10-31 11:33:43

輸出被回顯爲「陣列」:( – lock 2014-10-31 11:45:35

）您的意思是說，您沒有得到一個數組？您可以使用print_r（YOUR RETURN ARRAY）不使用echo作爲數組！ – 2014-10-31 11:48:03

輸出本身被打印爲「Array」 – lock 2014-10-31 11:48:34

問題是在$getval你只是存儲最後一個元素，

，你將需要做出這樣的數組也，像你在while循環

是如何做到的所有元素push()和返回數組

或剛剛返回$atradinghours這是所有的數據無論如何

來源

2014-10-31 11:33:52 user4185589

PHP打印使用While循環和陣列返回的所有值

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