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這是我在Arduino板上編程的第一年。出於某種原因,我的串口監視器不會接受任何用戶輸入,我做錯了什麼?我需要兩個用戶輸入作爲浮點變量,然後在我設置的自定義函數中使用。串行監視器不接受用戶輸入arduino c編程
float contSurfArea(float x, float y){
float z;
z = (3.14159*x*x)+(2*3.14159*x*y);
return (z);
}
void setup()
{
Serial.begin(9600); //serial communication initialized
}
void loop(){
float baseRad, contHeight;
Serial.println("Open-top Cylindrical Container Program");
delay(2000);
Serial.println("Radius of the base(in meters): ");
while(Serial.available()<=0)
baseRad= Serial.parseFloat();
delay(2000);
Serial.println("Height of the container(in meters): ");
while(Serial.available()<=0)
contHeight= Serial.parseFloat();
delay(2000);
float q;
q = contSurfArea(baseRad, contHeight);
Serial.print("The surface area of your container is: ");
Serial.print(q);
Serial.print("meters^2");
}
Pleasefixyourindentatiionelseyourcodeistoodifficulttoread – 2014-10-19 22:46:54