3
我有一個類Revision
,Revision
具有以下定義:涉及一類到它的自
class Revision(db.Model):
id = db.Column(db.Unicode, primary_key=True)
text = db.Column(db.Unicode)
此外,每個Revision
可以有一個祖先,如在另一Revision
的關係。每個Revision
也應該跟蹤任何接班人,即Revision
s,它作爲他們的祖先。我曾嘗試兩個以下:
ancestorId = db.Column(db.Unicode, db.ForeignKey("revision.id"))
successors = db.relationship("Revision", backref="ancestor", lazy="dynamic")
它扔:
sqlalchemy.exc.ArgumentError: Revision.successors and back-reference Revision.ancestor are both of the same direction <symbol 'ONETOMANY>. Did you mean to set remote_side on the many-to-one side ?
和
successors = db.relationship("Revision", backref="ancestor", lazy="dynamic")
它扔:
sqlalchemy.exc.ArgumentError: Could not determine join condition between parent/child tables on relationship Revision.successors. Specify a 'primaryjoin' expression. If 'secondary' is present, 'secondaryjoin' is needed as well.